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Basile [38]
3 years ago
8

Which polynomial function has a leading coefficient of 1 and roots 21 and 31 with multiplicity 1?

Mathematics
1 answer:
schepotkina [342]3 years ago
8 0

Answer:

Which i think is the first one, there may just be a typing error.

Step-by-step explanation:

A polynomial of order n has the following format:

f(x) = a(x - x_{0})(x - x_{1})...(x - x_{n-1})

In which a is the leading coefficient, x_{0}, x_{1},..., x_{n-1} are the roots.

If a root appears m times, they are said to have multiplicity m.

Leading coefficient of 1 and roots 21 and 31 with multiplicity 1

f(x) = 1(x - 21)(x - 31)

So the correct answer is:

f(x) = 1(x - 21)(x - 31)

Which i think is the first one, there may just be a typing error.

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Which answer is an equation in point-slope form for the given point and slope?
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Answer:

Step-by-step explanation:

Point-slope equation for line of slope m that passes through (x₀,y₀):

y-y₀ = m(x-x₀)

In your case, m=5 and (x₀,y₀)=(1,9):

y-9 = 5(x-1)

5 0
2 years ago
If the denominar is 25 what is the numrater
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7 0
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Please help me answer this!!
maksim [4K]
Well first you times the 0.3 to w and 10 which will give you 0.3w + 3 = 1.8w and subtracting 1.8 from 0.3 gives you
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I'm gonna cry I don't get this​
snow_tiger [21]

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d=14

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6 0
2 years ago
Read 2 more answers
Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth. x2 + 3 = 9x a 0.35, -8.65 b -0.35
Tema [17]
1. You have the following quadratic equation and to solve it, you must follow the steps below:
<span> 
 x</span>²<span>+3=9x
 
 2. The form of the equation that you need to apply the quadratic formula, is:
 
 ax</span>²+bx+c=0
<span> 
 3. Then:
</span> 
 x²<span>+3=9x
</span> x²-9x<span>+3=0
</span><span> 
 4. The quadratic formula is shown below:
 
 x=(-b±√(b^2-4ac))/2a
 
 5. Then, you have:
 
 a=1
 b=-9
 c=3
 
 6. When you substitute the values into the quadratic formula, you obtain:
 
 x1=0.34
 x2=8.65</span>
6 0
3 years ago
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