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Lilit [14]
3 years ago
6

as the schools sign language interpreter kiran gets paid 35.50 for every parent-teacher conference that he attends. He also gets

paid $42 per schhol-related assembly that he attends as an interpreter. If kiran earns $991 for 27 paid events how many parent teacher conferences and how many school related assemblies did he attend write a system of equations describe each variable and solve
Mathematics
2 answers:
yKpoI14uk [10]3 years ago
8 0

<u>The interpreter attended </u><u>22 parent-teacher conference</u><u> and </u><u>5 school related assembly</u>

To solve this problem, we would write out two set of linear equations.

The data given on this problem are

  • parent-teacher conference = $35.50
  • school related assembly = $42
  • The total number of engagements = 27

Let x represent the number of parent-teacher conference

let y represent the number of school related conference

<h3>Equations</h3><h3>x+y = 27...equation (i)\\35.50(x)+42y=991...equation(ii)</h3>

From equation (i)

x+y  = 27\\x = 27-y...equation(iii)\\

Put equation(iii) into equation (ii)

35.50x+42y=991\\35.50(27-y)+42y=991\\958.50-35.50y+42y=991\\6.50y=991-958.50\\y=5

Put y = 5 into equation 1

x+y=27\\y = 5\\x+5=27\\x=27-5\\x=22

From the above calculations, he attended 22 parent-teacher conference and 5 school related assembly.

Learn more on linear equations here;

brainly.com/question/4074386

I am Lyosha [343]3 years ago
4 0

Answer:

x= 22 (number of parent teacher conferences) y=5 (number of school related assemblies)

Step-by-step explanation:

This word problem creates the following system of equations for x = number of parent-teacher conferences and y = number of school related assemblies.

x+y = 27 means that the number of parent teacher conferences plus the number of school related assemblies equals a total of 27 paid events.

35.50x + 42y = 991 means that $35.50 multiplied by a certain number of parent teacher conferences, plus $42 multiplied by a certain number of school related assemblies equals his total earnings of $991.

This sets up the following system

x+y=27

35.50x+42y=991

To solve this, we first need to take the first equation and solve for y.

y=27-x

plug in to the second equation and solve for x.

35.50x+42(27-x)=991

35.50x-42x+1134=991

Collect like terms

-6.5x=-143

divide both sides by -6.5 to solve for x.

x=22

Back substitute into other original equation to solve for y.

22+y=27

y=5

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Answer: 36 degrees


Step-by-step explanation:

subtract 5 from 30=25

add 11 to 25

25+11=36



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100 - 12/n

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A teacher places n seats to form the back row of a classroom layout. Each successive row contains two fewer seats than the prece
Alex_Xolod [135]

Answer:

The number of seat when n is odd S_n=\frac{n^2+2n+1}{4}

The number of seat when n is even S_n=\frac{n^2+2n}{4}

Step-by-step explanation:

Given that, each successive row contains two fewer seats than the preceding row.

Formula:

The sum n terms of an A.P series is

S_n=\frac{n}{2}[2a+(n-1)d]

    =\frac{n}{2}[a+l]

a = first term of the series.

d= common difference.

n= number of term

l= last term

n^{th} term of a A.P series is

T_n=a+(n-1)d

n is odd:

n,n-2,n-4,........,5,3,1

Or we can write 1,3,5,.....,n-4,n-2,n

Here a= 1 and d = second term- first term = 3-1=2

Let t^{th} of the series is n.

T_n=a+(n-1)d

Here T_n=n, n=t, a=1 and d=2

n=1+(t-1)2

⇒(t-1)2=n-1

\Rightarrow t-1=\frac{n-1}{2}

\Rightarrow t = \frac{n-1}{2}+1

\Rightarrow t = \frac{n-1+2}{2}

\Rightarrow t = \frac{n+1}{2}

Last term l= n,, the number of term =\frac{ n+1}2, First term = 1

Total number of seat

S_n=\frac{\frac{n+1}{2}}{2}[1+n}]

    =\frac{{n+1}}{4}[1+n}]

     =\frac{(1+n)^2}{4}

    =\frac{n^2+2n+1}{4}

n is even:

n,n-2,n-4,.......,4,2

Or we can write

2,4,.......,n-4,n-2,n

Here a= 2 and d = second term- first term = 4-2=2

Let t^{th} of the series is n.

T_n=a+(n-1)d

Here T_n=n, n=t, a=2 and d=2

n=2+(t-1)2

⇒(t-1)2=n-2

\Rightarrow t-1=\frac{n-2}{2}

\Rightarrow t = \frac{n-2}{2}+1

\Rightarrow t = \frac{n-2+2}{2}

\Rightarrow t = \frac{n}{2}

Last term l= n, the number of term =\frac n2, First term = 2

Total number of seat

S_n=\frac{\frac{n}{2}}{2}[2+n}]

    =\frac{{n}}{4}[2+n}]

     =\frac{n(2+n)}{4}

    =\frac{n^2+2n}{4}  

4 0
3 years ago
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