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Volgvan
4 years ago
9

Does anyone know how to do this? How do you know if you do just 150=4x-6 OR 150+4x-6=180? I don’t understand how to tell which o

ne to use and I’m really struggling

Mathematics
1 answer:
sladkih [1.3K]4 years ago
4 0

Check the picture below.

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Se lanza un objeto desde una plataforma.
jasenka [17]

Answer:

6 seconds

Step-by-step explanation:

<u><em>The question in English is</em></u>

An object is thrown from a platform.

Its height (in meters), x seconds after launch, is modeled by:

h(x)=-5x^2+20x+60

How many seconds after the launch does the object reach the ground?

Let

x ----> the time in seconds

h(x) ---> the height of the object

we have

h(x)=-5x^2+20x+60

we know that

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so

For h(x)=0

we have

-5x^2+20x+60=60

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-5x^2+20x+60=60

so

a=-5\\b=20\\c=60

substitute in the formula

x=\frac{-20\pm\sqrt{20^{2}-4(-5)(60)}} {2(-5)}

x=\frac{-20\pm\sqrt{1,600}} {-10}

x=\frac{-20\pm40} {-10}

x=\frac{-20+40} {-10}=-2

x=\frac{-20-40} {-10}=6

The solution is x=6 sec

The he object reach the ground at x=6 seconds

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Please help me with this question
Nuetrik [128]

Answer:

false

Step-by-step explanation:

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Answer:

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Mathematics Answer

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