i. Let t be the line tangent at point J. We know that a tangent line at a point on a circle, is perpendicular to the diameter comprising that certain point. So t is perpendicular to JL
let l be the tangent line through L. Then l is perpendicular to JL ii. So t and l are 2 different lines, both perpendicular to line JL.
2 lines perpendicular to a third line, are parallel to each other, so the tangents t and l are parallel to each other.
Remark. Draw a picture to check the
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Betty's percentage is 15%.
The rate of change is the amount it changes for every missing assignment, therefore it would be -5.
Answer:
x° = 67°
Step-by-step explanation:
1. The first three diagrams are showing you that opposite exterior angles are congruent. Based on that, when you are faced with opposite exterior angles in the fourth diagram, you are able to conclude they are congruent. That means x° = 67°.
2. You can determine the other angles in the figure based on linear angles being supplementary, and same-side interior angles being supplementary. After you work through all the angles, you find that x = 67.
Answer:
y=1/2x+5
Step-by-step explanation:
y=mx+b
m is slope so the slope is 1/2.
