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Y_Kistochka [10]
2 years ago
12

A coin-operated drink machine was designed to discharge a mean of 6 ounces of coffee per cup. Suppose that we want to carry out

a hypothesis test to see if the true mean discharge differs from 6. State the null hypothesis h0 and the alternative hypothesis h1 that we would use for this test
Mathematics
1 answer:
lesya [120]2 years ago
6 0

Answer: H0 : u = 6 ounces

Ha : u not equal to 6 ounces

Step-by-step explanation:

The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean.

While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.

Therefore, for the case above;

H0 : u = 6

Ha : u not equal to 6.

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F(x)=3x−4g(x)=−x2+2x−5h(x)=2x2+1j(x)=6x2−8xk(x)=3x2−x+7 Calculate (fh)(x).
elena-s [515]

Answer:

( f h ) (x)  = 6 x² - 1

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given<em> f(x)   =  3 x - 4</em>

         g (x)  = −x²+2 x−5

      <em>   h (x)  = 2 x² + 1</em>

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<u><em>Step(ii)</em></u>:-

<em>( f h ) (x) = f ( h (x)) = f ( 2 x² + 1 )</em>

                            =  3 (2 x² + 1 ) - 4

                            =  3 ((2 x² ) + 3 - 4

                           =   <em>6 x² - 1</em>

<u><em> Final answer:</em></u>-

∴ <em> ( f h ) (x)  = 6 x² - 1</em>

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