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3 years ago

If angle x and angle y form a linear pair then they are ______ (Congruent, Complementary, Supplementary) ???

Mathematics

1 answer:

Law Incorporation [45]3 years ago

4 0

Answer:

They are supplementary.

Step-by-step explanation:

If two angles form a linear pair, the angles are supplementary.

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Graph x^4-3x^2+x. Identify the x-intercepts and the points where the local maximums and local minimums occur. Determine the inte

Brums [2.3K]

Functions, equations and tables can be represented using graphs

The x-intercepts are: 0, 0.35 and 1.53
The local maximum is at point (0.17, 0.08), and the local minimum is at point (1.13, -1.07)

The expression is given as:

$x^4-3x^2+x$

Rewrite the expression as a function

$f(x) = x^4-3x^2+x$

See attachment for the graph of the function.

<h3>The x-intercepts</h3>

This is the point where the graph cross the x-axis.

From the attached graph, the x-intercepts are: 0, 0.35 and 1.53

<h3>The local maximum</h3>

From the attached graph, the local maximum is at point (0.17, 0.08)

<h3>The local minimum</h3>

From the attached graph, the local minimum is at point (1.13, -1.07)

<h3>Intervals</h3>

The graph increases at interval (-1.30, 0) and (1,13, infinity)
The graph decreases at interval (- infinity, 1.30) and (0.35, 1.13)

Read more about graphs and functions at:

brainly.com/question/13136492

4 0

2 years ago

A man weighing 800 N is hanging from a 2 mm diameter titanium wire with a cross-section of 3 x 10^-6 m^2. Will the wire break?

DENIUS [597]

Answer:

Since stress is greater than ultimate strength, the wire will break.

Step-by-step explanation:

The titanium wire is experimenting an axial load. Ultimate strength equals $2.20\times 10^{8}\,Pa$ . The wire shall break if and only if stress is at least equal to ultimate strength. The equation for axial stress ( $\sigma$ ), measured in pascals, in the wire with circular cross-section is:

$\sigma = \frac{4\cdot F}{\pi\cdot D^{2}}$ (1)

Where:

$F$ - Axial force, measured in newtons.

$D$ - Cross-section diameter, measured in meters.

Please notice that axial force is the weight of the man hanging from wire.

If we know that $F = 800\,N$ and $D = 0.002\,m$ , then the axial stress experimented by the titanium wire is:

$\sigma = \frac{4\cdot (800\,N)}{\pi\cdot (0.002\,m)^{2}}$

$\sigma \approx 2.546\times 10^{8}\,Pa$

Since stress is greater than ultimate strength, the wire will break.

3 0

3 years ago

What is the equation of the line that passes through the point (-3, 6) and has a<br> slope of -1

mart [117]

Answer:

-9xy (xy+xy)-3

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Find the solution set of this system:

bezimeni [28]

Answer:

(−4, 12), (1, −3)

Step-by-step explanation:

y = −3x

x^2 −4 = y

x^2 −4 = −3x

x^2 + 3x - 4 = 0

(x + 4)(x - 1) = 0

x + 4 = 0; x = -4

x - 1 = 0; x = 1

when x = 1, y = -3(1) = -3

when x = -4, y = -3(-4) = 12

Answer

(-4 , 12), (1 , -3)

3 0

3 years ago

Read 2 more answers

Which of the following is a solution of the system 2x + y = 9 and 3x + 5y = 19.

Nezavi [6.7K]

2x+y=9

3x+5y=19

I will do this problem in 2 ways. I.)Substitution II.)Elimination

Solution I.) Substitution

We can subtract 2x from both sides in the first equation.

y=9-2x

Now we can substitute the y in the second equation with 9-2x

3x+5(9-2x)=19

-7x+45=19

-7x=-26

x=26/7

y=9-2(26/7)=11/7

Solution II.)Elimination

We can multiply both side of first equation by 5 to get a 5y in both equations.

10x+5y=45

Now because both are positive 5y we just need to do simple subtraction of the 2 equation, each side respectively.

(10x+5y)-(3x+5y)=45-19

7x=26

x=26/7

2*26/7+y=9

y=11/7

Ultimately you get the same answer, both are viable methods, some problems are faster with one method but I recommend mastering both since they are very useful.

4 0

3 years ago