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Viktor [21]
4 years ago
12

If x represents time, the average rate of change of the function f(x) in the first three seconds is ___.

Mathematics
2 answers:
DaniilM [7]4 years ago
7 0
<h2>Answer</h2>

If x represents time, the average rate of change of the function f(x) in the first three seconds is -50.

<h2>Explanation</h2>

The average rate of change of a linear function is the slope of the liner function. To find the slope of our linear function, we are using the slope formula:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

where

m is the slope of the line

(x_{1},y_{1}) are the coordinates of the first point on the line

(x_{2},y_{2}) are the coordinates of the second point

From our graph we can get the points (0, 150) and (3, 0), so x_{1}=0, y_{1}=150, x_{2}=3, and y_{2}=0. Let's replace the values in our formula to find the slope of our linear function:

m=\frac{0-150}{3-0}

m=\frac{-150}{3}

m=-50

Since the average of change a linear function is equal to its slope, the average rate of change of the function in the first three seconds is -50

Tresset [83]4 years ago
3 0
The average rate of change is -5/4
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During a nine-hour snowstorm, it snows at a rate of 2 inches per hour for the first 3 hours, at a rate of 3 inches per hour for
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Answer:

use f(x)=y=mx+b

let snow = S, time = t instead of y and x

S(t)=mt+b

The rate of inches per hour represents the slope of the graph, m.

The y-variable would be the amount of snow, S.

The x-variable would be the time, t, in hours.

The function has three pieces:

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For the first piece, i), t=3, so the amount of snow is 6 inches.

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Solve<br> 5(2x-y) = 7x + 1 <br> 3(3x+y) = 5(x-y+12)<br> using the elimination method<br> thanks!
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Answer:

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Solve the following system:

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{3 (3 x + y) = 5 (12 + x - y) | (equation 2)

Express the system in standard form:

{3 x - 5 y = 1 | (equation 1)

{4 x + 8 y = 60 | (equation 2)

Swap equation 1 with equation 2:

{4 x + 8 y = 60 | (equation 1)

{3 x - 5 y = 1 | (equation 2)

Subtract 3/4 × (equation 1) from equation 2:

{4 x + 8 y = 60 | (equation 1)

{0 x - 11 y = -44 | (equation 2)

Divide equation 1 by 4:

{x + 2 y = 15 | (equation 1)

{0 x - 11 y = -44 | (equation 2)

Divide equation 2 by -11:

{x + 2 y = 15 | (equation 1)

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Subtract 2 × (equation 2) from equation 1:

{x+0 y = 7 | (equation 1)

{0 x+y = 4 | (equation 2)

Collect results:

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