Answer: hello your question is poorly written below is the complete question
Let L be the set of all lines in XY plane and R be the relation in L defined as R = {(L1, L2): L1 is parallel to L2}. Show that R is an equivalence relation. Find the set of all lines related to the line y = 2x + 4.
answer:
a ) R is equivalence
b) y = 2x + C
Step-by-step explanation:
<u>a) Prove that R is an equivalence relation </u>
Every line is seen to be parallel to itself ( i.e. reflexive ) also
L1 is parallel to L2 and L2 is as well parallel to L1 ( i.e. symmetric ) also
If we presume L1 is parallel to L2 and L2 is also parallel to L3 hence we can also conclude that L1 is parallel to L3 as well ( i.e. transitive )
with these conditions we can conclude that ; R is equivalence
<u>b) show the set of all lines related to y = 2x + 4 </u>
The set of all line that is related to y = 2x + 4
y = 2x + C
because parallel lines have the same slopes.
Answer:
{y≥1
,{y-x>0
Step-by-step explanation:
First of all you have to consider the shaded region. It is bound by two lines.
The first line is a solid line that cuts the y-axis at +1. it's equation is y = 1. since the shade region is on the upper side where y values increase, the unequivocally will be y≥1. notice that the sign ≥ is due to the solid line which indicates points on the solid line are part of the solution.
the second line is the broken line. it passes through the origin (0,0) and (1,1) any two points can be taken. the gradient is 1. m= (y1-y2)/(x1-x2) = (0-1)/(0-1)=(-1/-1)= 1. the equation of a straight line is
y=mx + c where m is gradient and c is the VA)ue of y as the line crosses the y axis ( y-intercept) which in this case is 0 at (0,0).so the equation will be y=1(x) + 0
y=x if we subtract x from both sides we have
y-x=0
since the shaded region is on the upper side as y-x increases the in equality will be
y-x>0 notice since the line is broken it shall be just > not≥ because points on a broken line are not included in the shaded region.
Answer:
x=y/9
Step-by-step explanation:
Answer:
82 seats
Step-by-step explanation:
50+4x(number row - 1)
50+4x(9-1)
50+4x8
50+32
82 seats for the ninth row
