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allochka39001 [22]
3 years ago
6

On a math test. Olivia is told that the points (1,3) and (3,0) are two of the vertices of a square.

Mathematics
1 answer:
galben [10]3 years ago
7 0
It sounds like its A. not for sure
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Solve in attachment....​
olga2289 [7]

Answer:

A)2

Step-by-step explanation:

we would like to integrate the following definite Integral:

\displaystyle  \int_{0} ^{1} 5x \sqrt{x} dx

use constant integration rule which yields:

\displaystyle  5\int_{0} ^{1} x \sqrt{x} dx

notice that we can rewrite √x using Law of exponent therefore we obtain:

\displaystyle  5\int_{0} ^{1} x \cdot  {x}^{1/2} dx

once again use law of exponent which yields:

\displaystyle  5\int_{0} ^{1}  {x}^{ \frac{3}{2} } dx

use exponent integration rule which yields;

\displaystyle  5 \left( \frac{{x}^{ \frac{3}{2}  + 1  } }{ \frac{3}{2}  + 1} \right)  \bigg|  _{0} ^{1}

simplify which yields:

\displaystyle  2 {x}^{2}  \sqrt{x}   \bigg|  _{0} ^{1}

recall fundamental theorem:

\displaystyle  2 (  {1}^{2}) (\sqrt{1}  ) - 2( {0}^{2} )( \sqrt{0)}

simplify:

\displaystyle  2

hence

our answer is A

8 0
3 years ago
Read 2 more answers
Someone plz help me with this
Phoenix [80]

Answer:

5y^{6}\sqrt{2}

Step-by-step explanation:

We want to  simplify:

\sqrt{50y^{12}}

We rewrite as:

\sqrt{2\times25 \times (y^{6})^2}

We split the radical sign to obtain:

\sqrt{25} \times \sqrt{(y^{6})^2} \times \sqrt{2}

Simplify the square root for the perfect squares to get:

5y^{6}\sqrt{2}

Therefore the simplified form is: 5y^{6}\sqrt{2}

8 0
3 years ago
Given: f(x) = 3x2 + 2x – 1
denis-greek [22]

Answer:

84

Step-by-step explanation:

f(x) = 3x^2 + 2x – 1

Let x=5

f(5) = 3(5)^2+2(5) -1

     = 3*25 +10-1

    = 75+10 -1

    = 85 -1

4 0
3 years ago
Round the following times to 1 decimal place 8.16
Mekhanik [1.2K]
The answer is 8.2 bc anything above a 5 goes up.
8.16 <<< a 6 is greater than 5. So the 1 goes up to a 2.
4 0
3 years ago
-3(4x-8.2)&lt; -11.98x + 14 3 /4
Leona [35]
The answer would be C
6 0
4 years ago
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