Step-by-step Answer:
There is a total of 10 coins, 5 dimes, 2 quarters and three pennies.
By picking a coin, it could be any that shows up out of the 10, so the probability of picking any coin in particular is 1 / 10.
If there are 5 dimes, the probability of picking ANY one particular dime is 1/10, so with 5, the probability of picking ANY of the five dimes is 5/10 = 1/2.
Going along the same line of thought, the probability of picking any of quarters and pennies would be 2/10+3/10 = 5/10 = 1/2 as well.
Answer:
.4=a
Step-by-step explanation:
self explanatory
Answer:
Step-by-step explanation:
the second one is correct. the first one is wrong because shape C also has those angles. the third one is wrong because shape C also has no perpendicular sides. the fourth one is wrong because shape C also has 2 pairs of angles with the same measure.
Answer:
2.28% of tests has scores over 90.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What proportion of tests has scores over 90?
This proportion is 1 subtracted by the pvalue of Z when X = 90. So
has a pvalue of 0.9772.
So 1-0.9772 = 0.0228 = 2.28% of tests has scores over 90.
Answer:
y=-6+5
Step-by-step explanation:
