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nevsk [136]
3 years ago
7

What is an equation of the line that passes through the point (-6,7) and is perpendicular to the line

Mathematics
1 answer:
Temka [501]3 years ago
5 0

The equation of line perpendicular to given line through (-6,7) is:

y=\frac{1}{6}x+8

Further explanation:

Given equation of line is:

6x+y=3\\y= -6x+3

The co-efficient of x is the slope of given line.

Let m1 be the slope of given line

and

m2 be the slope of line perpendicular to given line

Then

m_1=-6

Product of slopes of perpendicular lines is -1

m_1*m_2 = -1\\-6*m_2=-1\\m_2=\frac{-1}{-6}\\m_2=\frac{1}6}

The equation of new line can be written as:

y=m_2x+b\\

Putting m2

y=\frac{1}{6}x+b

To find the value of b, we will put (-6,7) in equation

7=\frac{1}{6}(-6)+b\\7=-1+b\\b=7+1\\b=8

Putting the values of b and m in general equation

y=\frac{1}{6}x+8

Keywords: Slope, Point-slope form, perpendicular lines

Learn more about perpendicular lines at:

  • brainly.com/question/12941985
  • brainly.com/question/4152194

#LearnwithBrainly

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