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nirvana33 [79]
3 years ago
11

Help!!!!!!!!!!!!!!!!!!

Physics
1 answer:
GREYUIT [131]3 years ago
5 0
I think wind is anther answer
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Pls answer B And C Will Mark Brainlist. And 30 Points. :)
Vika [28.1K]

Answer:

use the formula for option B ( d/t = s )

and

look at the graph representation to explain

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3 years ago
What is the precision for each measurement for the online simulation. What would be the precision for force
zimovet [89]

Answer:

Unit of precision for force is the Newton.

Explanation:

It is the official unit used to describe force in science and mostly abbreviated with the symbol N.

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What’s the equalibrium rule?
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The vector sum of forces acting on a non-accelerating object equals zero.
equation form: ΣF = 0
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3 years ago
Read 2 more answers
What can you say about the magnitudes of the forces that the balloons exert on each other?
maxonik [38]

Answer:

F_G=G. \frac{m_1.m_2}{R^2} gravitational force

F=\frac{1}{4\pi \epsilon_0} \times \frac{q_1.q_2}{R^2} electrostatic force

Explanation:

The forces that balloons may exert on each other can be gravitational pull due to the mass of the balloon membrane and the mass of the gas contained in each. This force is inversely proportional to the square of the radial distance between their center of masses.

The Mutual force of gravitational pull that they exert on each other can be given as:

F_G=G. \frac{m_1.m_2}{R^2}

where:

G= gravitational constant  =6.67\times 10^{-11} m^3.kg^{-1}.s^{-2}

m_1\ \&\ m_2 are the masses of individual balloons

R= the radial distance between the  center of masses of the balloons.

But when  there are charges on the balloons, the electrostatic force comes into act which is governed by Coulomb's law.

Given as:

F=\frac{1}{4\pi \epsilon_0} \times \frac{q_1.q_2}{R^2}

where:

\rm \epsilon_0= permittivity\ of\ free\ space

q_1\ \&\ q_2 are the charges on the individual balloons

R = radial distance between the charges.

3 0
3 years ago
1 If you measured the distance travelled by a snail in
Fittoniya [83]
The answer is m/s hope it helps
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2 years ago
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