Explanation:
<em>Given </em>
<em>Mass </em><em>(</em><em>m) </em><em> </em><em>=</em><em> </em><em>2</em><em> </em><em>kg</em>
<em>Force </em><em>(</em><em>F) </em><em> </em><em>=</em><em> </em><em>1</em><em> </em><em>N</em>
<em>Acceleration </em><em>(</em><em>a) </em><em> </em><em>=</em><em> </em><em>?</em>
<em>We </em><em>have </em><em>the </em><em>formula </em><em>that </em>
<em>F </em><em>=</em><em> </em><em>m </em><em>*</em><em> </em><em>a</em>
<em>1</em><em> </em><em>=</em><em> </em><em>2</em><em> </em><em>*</em><em> </em><em>a</em>
<em>a </em><em>=</em><em> </em><em>1</em><em>/</em><em>2</em><em> </em>
<em>Therefore </em><em>acceleration </em><em>=</em><em> </em><em>0</em><em>.</em><em>5</em><em> </em><em>m/</em><em>s</em><em>²</em>
Answer:
a = 2d / t²
or
a = 2gh / (3d)
Explanation:
One method is to use the equation:
Δx = v₀ t + ½ at²
d = (0) t + ½ at²
d = ½ at²
a = 2d / t²
By measuring the length of the incline d, and the time it takes to reach the bottom t, the students can calculate the acceleration, using only the meter stick and the stopwatch.
Another method is to use conservation of energy to find the final velocity.
Initial potential energy = final rotational energy + kinetic energy
PE = RE + KE
mgh = ½ Iω² + ½ mv²
For a solid cylinder, I = ½ mr². For rolling without slipping, ω = v/r.
mgh = ½ (½ mr²) (v/r)² + ½ mv²
mgh = ¼ mv² + ½ mv²
mgh = ¾ mv²
4gh/3 = v²
Using constant acceleration equation:
v² = v₀² + 2aΔx
4gh/3 = 0² + 2ad
a = 2gh / (3d)
Using this equation, the students can measure the height of the incline h, and the length of the incline d, to calculate the acceleration. The only equipment needed is the meter stick.
Answer:
v = 12.12 m/s
Explanation:
Given that,
Radius of the curvature, r = 30 m
To find,
The car's speed at the bottom of the dip.
Solution,
Let mg is the true weight of the passenger. When it is moving in the circular path, the centripetal force act on it. It is given by :
The normal reaction of the passenger is given by :
N = 1.5 mg
Let v is the car's speed at the bottom of the dip. It can be calculated as:
v = 12.12 m/s
So, the speed of the car at the bottom of the dip is 12.12 m/s. Hence, this is the required solution.
Answer:zero
Explanation:
Work done in moving a charge is zero in equipotential surface because potential of each point is same .
When there is Potential gradient then some particle experiences a force while moving but in equipotential surface there is no potential gradient , that is why work done in moving a charge is zero.
B) compound.
A compound is usually made up of different Elements, a compound is likely to have a melting point as well.
