Question

A proton moves 0.10 m along the direction of an electric field of magnitude 3.0 V/m. What is the change in kinetic energy of the proton? (e = 1.60 × 10-19 C)

Answer 1

The change in kinetic energy of the proton is 4.8 x 10⁻²⁰.

Change in kinetic energy of the proton

The change in kinetic energy of the proton is calculated as follows;

ΔK.E = W = eV

where;

• V is the potential difference
• e is charge of electron

V = Ed

V = 3 V/m x 0.1 m = 0.3 V

ΔK.E  = 1.6 x 10⁻¹⁹ x 0.3 = 4.8 x 10⁻²⁰ J

Thus, the change in kinetic energy of the proton is 4.8 x 10⁻²⁰ J.

Learn more about kinetic energy here: brainly.com/question/25959744
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