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damaskus [11]
3 years ago
13

What is the surface area of the figure shown? Plz answer asap

Mathematics
1 answer:
Luba_88 [7]3 years ago
3 0

Answer:

264\ cm^{2}

Step-by-step explanation:

we know that

The surface area of the figure is equal to the lateral face of the triangular pyramid plus the lateral face of the rectangular prism plus the area of the base of the rectangular prism

step 1

Find the lateral face of the triangular prism

The lateral area is equal to the area of its four lateral triangular faces

LA=4(\frac{1}{2}(6)(7))=84\ cm^{2}

step 2

Find the lateral area of the rectangular prism

The lateral area is equal to the perimeter of the base multiplied by the height

LA=(4)(6)(6)=144\ cm^{2}

step 3

Find the area of the base of the rectangular prism

B=(6)(6)=36\ cm^{2}

step 4

Find the surface area

84\ cm^{2}+144\ cm^{2}+36\ cm^{2}=264\ cm^{2}

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In ΔKLM, l = 2.4 inches, m = 4.2 inches and ∠K=159°. Find the length of k, to the nearest 10th of an inch.
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6.5

Step-by-step explanation:

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A lot is 60m by 34 m. A house 25 m by 9 m on the lot. How much area is left over
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Answer:

The left over area is 1,815 m.

Step-by-step explanation:

60x34= 2,040

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Multiply<br> (2x + 4)(2x - 4)
lakkis [162]

Answer:

4x^2 -16

Step-by-step explanation:

(2x + 4)(2x - 4)

FOIL

first:2x*2x = 4x^2

outer: -4 *2x = -8x

inner:  4*2x = 8x

last: -4*4 = -16

Add them together

4x^2 -8x+8x =-16

4x^2 -16

8 0
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Read 2 more answers
Exercise 1.1. We roll a fair die twice. Describe a sample space ⌦ and a probability measure P to model this experiment. Let A be
3241004551 [841]

Answer:

P=\frac{1}{36}

P(A)=\frac{5}{12}

Step-by-step explanation:

The sample space of rolling a dice twice is:

S = {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)

       (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)

       (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)

       (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)

       (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)

       (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

Sample size, <em>n</em> = 36.

Each sample has an equal chance of being selected.

So the probability of selecting any of the 36 sample is, P=\frac{1}{36}.

Now an event <em>A</em> is defined as the second roll being larger than the first.

The sample space for <em>A</em> is:

<em>A</em> = {(2, 1), (3, 1), (3, 2), (4, 1), (4, 2), (4, 3), (5, 1), (5, 2), (5, 3), (5, 4), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5)}

The sample size is, <em>n</em> = 15.

The probability of the event <em>A</em> is:

P(A)=\frac{15}{36}=\frac{5}{12}

5 0
3 years ago
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