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LUCKY_DIMON [66]
3 years ago
12

Shawna found coins worth $4.32. One- fourth of the found coins are pennies and one- sixth are quarters. The number of nickels fo

und are 1.5 times the amount of quarters. How many of each coin did Shawna find?
Mathematics
1 answer:
eduard3 years ago
8 0

Answer:

8 quarters

12 nickels

12 pennies

16 dimes

Step-by-step explanation:

The trick is to ASSUME the dimes.

Start by thinking about the three explicit premises and the one implicit premise.

1) Quarters = 1/6 of total coins

2) Nickels = 1.5 the number of quarters

3) Pennies = 1/4 of total coins

Also, ASSUME an unknown number of dimes to fill in the gap.

48 Total Coins = $4.32

⅙ of 48 = 8 8 quarters = $2.00

1.5 x 8 = 12 12 nickels = $0.60

¼ of 48 = 12 12 pennies = $0.12

Add those coins = $2.72

Take the known total and minus this sum.

$4.32 - $2.72 = $1.60

16 dimes = $1.60

Thus, you have the following:

8 quarters (⅙ of total coins)   $2.00

12 nickels (1.5 the number of quarters) $0.60

12 pennies (¼ the number of total coins) $0.12    

+ 16 dimes     $1.60

Total Coins 48      $4.32

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which of the following represents the equation of the line with an x- intercept of 6 that passes through the point (4,4)?
luda_lava [24]

Answer:

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If the area of a rectangle with width x can be represented with the expression A(x) = x(14 – x), what is the perimeter of the re
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A=WL
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A=(x)(14-x)
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