Look where the line is touching on the y-axis and that will be your y-value. From there or somewhere on the line use rise over run (rise/run, do not divide). Count how many times it goes up and then count how many times it goes left or right. Make sure to look where the line is going, up or down slanted. If the line is going down, but slanted it will be a negative slope; line going up and slanted is positive.
What is the standard deviation of the data set?
6, 4, 9, 5, 5, 4, 5
Round the answer to the tenths place.What is the standard deviation of the data set?
6, 4, 9, 5, 5, 4, 5
Round the answer to the tenths place.
Step-by-step explanation:
ERFSDFNJKOODSJNFIODSJIFJDSIOFDSF
Answer:
forty point five hundred forty-five
Step-by-step explanation:
Answer:
The equation of any straight line, called a linear equation, can be written as: y = mx + b, where m is the slope of the line and b is the y-intercept. The y-intercept of this line is the value of y at the point where the line crosses the y axis.
so to find that you can use y=mx+b, or you can use point slope form and that would be y-y1+m(x-x1)
remember m= slope b= y- intercept
X + y = 5
xy = 12
x + y = 5
y = -x + 5
xy = 12
x(-x + 5) = 12
x(-x) + x(5) = 12
-x² + 5x = 12
- 12 - 12
-x² + 5x - 12 = 0
x² - 5x + 12 = 0
x = 5 ± √25 - 48
2
x = -5 ± √-23
2
x = -5 ± 4.79i
2
x = -5 + 4.79i or x = -5 - 4.79i
2 2
x = -2.5 + 2.395i or x = -2.5 - 2.395i
y = -2.5 - 2.395i or y = -2.5 + 2.395i
The two numbers that add up to 5 and multiply to 12 is -2.5 ± 2.395i, which is -2.5 + 2.395i and -2.5 - 2.395i.
