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sasho [114]
3 years ago
12

Micah walks 3/5 mile to the playground, 3/8 mile to a friend’s house, and then 1 1/10 miles to the library. About how many miles

did Micah walk in all?
Mathematics
1 answer:
posledela3 years ago
6 0

Answer:

2.075 Miles

Step-by-step explanation:

3/5 x 8 = 24/40

3/8 x 5 = 15/40

11/10 x 4 = 44/40

24 + 15 + 44 = 83

83/40 = 2.075

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A _______has one endpoint line or ray
Nikolay [14]

Answer:

Ray.

Step-by-step explanation:

Lines have no endpoints, while rays have 1 endpoint (:

7 0
2 years ago
An angle bisector of a triangle divides the opposite side of the triangle into segments 5 cm and 3 cm long. A second side of the
attashe74 [19]
There is a little-known theorem to solve this problem.

The theorem says that
In a triangle, the angle bisector cuts the opposite side into two segments in the ratio of the respective sides lengths.

See the attached triangles for cases 1 and 2.  Let x be the length of the third side.

Case 1:
Segment 5cm is adjacent to the 7.6cm side, then
x/7.6=3/5  => x=7.6*3/5=4.56 cm

Case 2:
Segment 3cm is adjacent to the 7.6 cm side, then
x/7.6=5/3 => x=7.6*5/3=12.67 cm

The theorem can be proved by considering the sine rule on the adjacent triangles ADC and BDC with the common side CD and equal angles ACD and DCB.

6 0
3 years ago
Find the value of x.
murzikaleks [220]
70 it has to equal 180
5 0
2 years ago
The value of a boat if depreciating at at a rate of 9% per year. In 2006 the boat was worth $17,800. Find the worth of the boat
svetlana [45]

Answer:

The worth of boat in 2013 will be $9202.6

Step-by-step explanation:

Rate of depreciation = 9% = 0.09

Cost of Boat in 2006 =$ 17,800

Cost of Boat in 2013 = ?

Years = 2013-2006= 7 years

The formula used is: \mathbf{A=P(1+r)^{t}}

Since the value of boat is depreciating the value of r will be r=-0.09

Here P = 17,800 , r=-0.09 and t = 7 years Finding A

A=P(1+r)^{t}\\A=17,800(1+(-0.09))^7\\A=17,800(0.91)^7\\A=17,800(0.517)\\A=9202.6

So, the worth of boat in 2013 will be $9202.6

4 0
2 years ago
Express cos(27pi/8) as a trigonometric function of an angle in Quadrant I.
Kryger [21]

Answer:

The equivalent trigonometric ratio in Quadrant I is -\cos (\frac{3\pi}{8})

Step-by-step explanation:

The terminal side of \frac{27\pi}{8} is in the 3rd quadrant.

The principal angle is \frac{3\pi}{8}

In other words, the terminal side of \frac{27\pi}{8}  makes an acute angle of \frac{3\pi}{8} radian with the positive x-axis. Acute angles are in the first quadrant.

Since the cosine ratio is negative in the 3rd quadrant,

\cos (\frac{27\pi}{8})=-\cos (\frac{3\pi}{8})

3 0
3 years ago
Read 2 more answers
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