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muminat
3 years ago
9

A group of vacationing gamblers were asked which casino games they had played to date. 5 gamblers said they played blackjack, ro

ulette, and poker. • 8 gamblers said they played roulette and poker. • 11 gamblers said they played blackjack and roulette. • 12 gamblers said they only played poker. 24 gamblers said they played poker. How many gamblers played exactly two games?
Mathematics
1 answer:
leonid [27]3 years ago
7 0

Answer: There are 13 gamblers who played exactly two games.

Step-by-step explanation:

Since we have given that

Number of gamblers played black jack, roulette and poker = 5

Number of gamblers played roulette and poker = 8

Number of gamblers played black jack and roulette = 11

Number of gamblers played only poker = 12

Number of gamblers played poker = 24

Number of gamblers who played only roulette and poker is given by

8-5=3

Number of gamblers who played only black jack and roulette is given by

11-5=6

Number of gamblers who played only poker and black jack is given by

24-(12+3+5)\\\\=24-20\\\\=4

So, the number of gamblers who played exactly two games is given by

3+6+4=13

Hence, there are 13 gamblers who played exactly two games.

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Which statement about g(x)=x^2-576 is true
Rus_ich [418]

Answer:

Option C.

The zeros, -24 and 24, can be found when 0= (x+24)(x-24).

Step-by-step explanation:

we have

g(x)=x^{2}-576

we know that

To find the zeros, equate the equation to zero

x^{2}-576=0

x^{2}=576

square root both sides

x=(+/-)24

therefore

0=(x+24)(x-24)

3 0
4 years ago
Find the circumference of a circle whose area is 24 pi ft ^2
lianna [129]
\bf \textit{area of a circle}\\\\
A=\pi r^2~~
\begin{cases}
r=radius\\
-----\\
A=24\pi 
\end{cases}\implies 24\pi =\pi r^2\implies \cfrac{24\pi }{\pi }=r^2
\\\\\\
24=r^2\implies \boxed{\sqrt{24}=r}\\\\
-------------------------------\\\\
\textit{circumference of a circle}\\\\
C=2\pi r\qquad \qquad \implies C=2\pi\left( \boxed{\sqrt{24}} \right)~~
\begin{cases}
24=2\cdot 2\cdot 2\cdot 3\\
\qquad 2^2\cdot 6
\end{cases}
\\\\\\
C=2\pi \sqrt{2^2\cdot 6}\implies C=2\pi (2\sqrt{6})\implies C=4\sqrt{6}~\pi
3 0
3 years ago
So the question is "Write down four common multiples of 2 and 3"<br> Step by step explaination :(
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Answer:

The common multiples of 2 and 3 are 6,12,18,24

Multiples of 2: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24...

Multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24, 27...

Common multiples of 2 and 3 include 6, 12, 18, and 24.

6 0
3 years ago
Mel is taking her holidays. She receives $2937.50. This includes her normal pay
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8 0
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PLEASE HELP!!! Write the equation of a line that goes through the point (6, 3) and is perpendicular to the line y = 4x + 1.
Tpy6a [65]

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y-y_ {0} = m (x-x_ {0})

Where:

m: It is the slope of the line and (x_ {0}, y_ {0})is a point through which the line passes.

We have the following equation of the slope-intersection form:

y = 4x + 1

Where the slope is m = 4

By definition, if two lines are perpendicular then the product of their slopes is -1.

Thus, a perpendicular line will have a slope:

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Thus, the equation will be of the form:

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8 0
3 years ago
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