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VMariaS [17]
3 years ago
10

What is the gcf of 49 and 63

Mathematics
2 answers:
ValentinkaMS [17]3 years ago
4 0
The greatest common factor for 49 and 63 would be 7 since you can divide 7 into both numbers perfectly

musickatia [10]3 years ago
3 0
The gcf of 49 and 63 is 7 because i wrote down all factors of 49 and 63 and i found the highest common factor,which was 7.
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Hannah and Dawson have both invested money in savings accounts with APYs of 3.2%. If Hannah's account has a balance of $31,000 a
9966 [12]

Answer:

$341.07

Step-by-step explanation:

Hanna and Dawson both invested at 3.2% = 0.032

Hannah has balance of 31,000 in account

Dawson has balance of 42000 in account

Interests earned by both are

1)Hannah -P(1+i)^-n

=31000(1+0.032)^-1

=31000(1.032)^-1

=31000(0.968992)

=$30038.752

=$30038.75

Interest earned by Dawson is $31,000 - $30038.75 = $961.25

2)Dawson-  P(1+i)^-n

=42000(1+0.032)^-1

=42000(1.032)^-1

=42000(0.968992)

=$40697.664

=$$40697.664

Interest earned by Dawson is $42,000 - $40697.66= $1302.32

3) Hence the amount that Dawson earns than is:

=$1302.32-$961.25

= $341.07

3 0
3 years ago
A bag contains 6 yellow marbles and 18 red. If a representative sample contains 2 yellow marbles, then how many red would you ex
kramer

Answer:

6 red marbles

Step-by-step explanation:

We must first find our multiplier since a sample represents a population (the whole thing).

6/2 = 3, so 3 * 2 = 6.

I will use the value of 6/2, aka 3 and use that as my divisor.

18/3 = 6.

Therefore, you would expect to have 6 red marbles.

3 0
3 years ago
HELP ASAP ILL GIVE BRAINLIST
Mila [183]

Answer:

Part A)  ΔCGB and ΔPBE are similiar

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Step-by-step explanation:

5 0
2 years ago
The angles of a quadrilateral measure 80° 100° 100° and 80° In this order what kind of quadrilateral has this shape?
NemiM [27]

Answer:

The answer is a isosceles trapezoid.

Hope this helps!

brainliest? :)

8 0
3 years ago
Read 2 more answers
After traveling exactly half of its journey from station A to station B, a train was held up for 10 minutes. In order to arrive
Alex17521 [72]
Let's define variables:
 s = original speed
 s + 12 = faster speed
 The time for the half of the route is:
 60 / s
 The time for the second half of the route is:
 60 / (s + 12)
 The equation for the time of the trip is:
 60 / s + 60 / (s + 12) + 1/6 = 120 / s
 Where,
 1/6: held up for 10 minutes (in hours).
 Rewriting the equation we have:
 6s (60) + s (s + 12) = 60 * 6 (s + 12)
 360s + s ^ 2 + 12s = 360s + 4320
 s ^ 2 + 12s = 4320
 s ^ 2 + 12s - 4320 = 0
 We factor the equation:
 (s + 72) (s-60) = 0
 We take the positive root so that the problem makes physical sense.
 s = 60 Km / h
 Answer:
 
The original speed of the train before it was held up is:
 
s = 60 Km / h
8 0
3 years ago
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