Question

What mass of carbon dioxide is produced from the complete combustion of 6.00×10−3 g of methane?

Answer 1

The answer for the following problem is explained below.

• Therefore 16.5 × 10^-3 grams of carbon dioxide is produced from the complete combustion.

Explanation:

Given:

mass of methane = 6.00 × 10^-3 grams

$CH_{4}$ + $O_{2}$ → $CO_{2}$ + $H_{2}O$

Firstly balance the following equation:

Before balancing the equation:

$CH_{4} + O_{2}$ → $CO_{2} + H_{2} O$

After balancing the equation:

$CH_{4} + 2O_{2}$ → $CO_{2} + 2 H_{2} O$

where;

$CH_{4}$  represents methane molecule

$O_{2}$ represents oxygen molecule

$CO_{2}$  represents carbon dioxide molecule

$H_{2}O$  represents water molecule

 

       $CH_{4}$ +2 $O_{2}$ → $CO_{2}$ + 2$H_{2}O$

        16  grams of methane       →        44 grams of carbon dioxide

        6 × 10^-3 grams of methane →          ?

                 = $\frac{44*6.00*10^{-3} }{16}$

          = 16.5 × 10^-3 grams of carbon dioxide is produced from the complete combustion.

Therefore 16.5 × 10^-3 grams of carbon dioxide is produced from the complete combustion.