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Nimfa-mama [501]
2 years ago
15

g Imagine that you found a piece of carved wood that has been embedded in glacial ice. The mass of the wood is 50 grams, and 30%

of the mass is carbon. The 14C/12C ratio of the wood was measured by mass spectrometry, and found to be 20 % of the 14C/12C ratio found in CO2 in modern air. You may assume that the half life of 14C is 5700 years. Which is the best estimate of the age of the wood
Chemistry
1 answer:
astra-53 [7]2 years ago
4 0

Answer:

13414 years

Explanation:

From;

0.693/ t1/2 = 2.303/t log No/N

t1/2 = half life of  C-14

t = age of the sample

No= initial amount of C-14

N = present amount of C-14

From the question, N = 0.2 No

Hence;

0.693/5700 = 2.303/t log No/0.2No

1.2 * 10^-4 = 2.303/t log 1/0.2

1.2 * 10^-4 = 1.6097/t

t = 1.6097/1.2 * 10^-4

t = 13414 years

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C

Explanation:

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D

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6 0
2 years ago
Read 2 more answers
Can someone help me with number 1 and 2 plz!
GalinKa [24]

Answer:

1) 0 N

2) 8 N

Explanation:

The net force is the sum of all of the forces acting on the object.

For question 1, we can see that there is a force of 5 N acting to the right and 5 N acting to the left.  If we define the right to be positive and the left to be negative, then the net force equals:

Fnet = 5N - 5N = 0 N

Therefore, the net force in question 1 is 0 N.

For question 2, the process is very similar.  We want to find the sum of the forces acting on the object.  In this case, there are forces of 3 N and 5 N acting to the right.

Fnet = 3 N + 5 N = 8 N

Therefore, the net force in question 2 is 8 N.

Hope this helps!

3 0
2 years ago
The acid dissociation constant Ka of boric acid (H3BO3) is 5.8 times 10^-10. Calculate the pH of a 4.4 M solution of boric acid.
madam [21]

Answer: The pH of a 4.4 M solution of boric acid is 4.3

Explanation:

H_3BO_3\rightarrow H^+H_2BO_3^-

at t=0  cM              0             0

at eqm c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 4.4 M and \alpha = ?

K_a=5.8\times 10^{-10}

Putting in the values we get:

5.8\times 10^{-10}=\frac{(4.4\times \alpha)^2}{(4.4-4.4\times \alpha)}

(\alpha)=0.000011

[H^+]=c\times \alpha

[H^+]=4.4\times 0.000011=4.8\times 10^{-5}M

Also pH=-log[H^+]

pH=-log[4.8\times 10^{-5}]=4.3

Thus pH of a 4.4 M H_3BO_3 solution is 4.3

3 0
3 years ago
Select the correct answer. What is the enthalpy for the reaction represented in the following energy diagram? A. +200 kJ B. +350
Stella [2.4K]

Answer:

Option C. +150KJ

Explanation:

Data obtained from the question include:

Heat of reactant (Hr) = 200KJ

Heat of product (Hp) = 350KJ

Change in enthalphy (ΔH) =..?

The enthalphy of the reaction can be obtained as follow:

Change in enthalphy (ΔH) = Heat of reactant (Hp) – Heat of reactant (Hr)

ΔH = Hp – Hr

ΔH = 350 – 200

ΔH = +150KJ

Therefore, the enthalphy for the reaction above is +150KJ

6 0
2 years ago
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