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fiasKO [112]
3 years ago
14

A substance has a melting point of 0��c and a boiling point of 100��c. the substance is most likly?

Chemistry
2 answers:
seraphim [82]3 years ago
7 0

Answer:

<h2><em><u>The substance is most likely water (H2O).</u></em></h2><h2>plz.. mark me as brainiest :D</h2>
ratelena [41]3 years ago
6 0
The substance is most likely water (H2O).
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The following reaction shows the products when sulfuric acid and aluminum hydroxide react.
SSSSS [86.1K]

Answer:

There will remain 11.47 grams of Al(OH)3

Explanation:

Step 1: Data given

Mass of sulfuric acid = 35.0 grams

Molar mass sulfuric acid = 98.08 g/mol

Mass of aluminium hydroxide = 30.0 grams

Molar mass of aluminium hydroxide = 78.0 g/mol

Step 2: The balanced equation

2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O

Step 3: Calculate moles

Moles = mass / molar mass

Moles Al(OH)3 = 30.0 grams / 78.0 g/mol

Moles Al(OH)3 = 0.385 moles

Moles H2SO4 = 35.0 grams / 98.08 g/mol

Moles H2SO4 = 0.357 moles

Step 4: Calculate the limiting reactant

For 2 moles Al(OH)3 we need 3 moles H2SO4 to produce 1 mol Al(SO4)3 and 6 moles H20

H2SO4 is the limiting reactant. It will completely be consumed ( 0.357 moles). Al(OH)3 is in excess. There will be react 2/3 * 0.357 = 0.238 moles

There will remain 0.385 - 0.238 = 0.147 moles

Mass of Al(OH)3 remaining = 0.147 moles* 78.0 g/mol = 11.47 grams

There will remain 11.47 grams of Al(OH)3

6 0
3 years ago
For the reaction 2Na + 2H20 - 2NaOH + H2 how many grams of sodium hydroxide are
ololo11 [35]

Answer:

Explanation:

Moles of sodium

=

130

⋅

g

22.99

⋅

g

⋅

m

o

l

−

1

=

5.65

⋅

m

o

l

.

Now you have the stoichiometric equation:

2

N

a

(

s

)

+

2

H

2

O

(

l

)

→

2

N

a

O

H

(

a

q

)

+

H

2

(

g

)

↑

⏐

If there are

5.65

⋅

m

o

l

of metal, clearly

5.65

⋅

m

o

l

2

dihydrogen gas are evolved......, i.e.

2.83

⋅

m

o

l

H

2

. Typically, in a question like this, you would also be asked to calculate the volume the gas occupies under standard conditions, and the

p

H

of the resultant solution (would it be high, low, neutral?).

3 0
4 years ago
Read 2 more answers
GOLF BALL PROPERTIES 1. Gabriel uses these numbers to find the density of the golf balls. Water has a density of 1.0 g/cm3. Whic
vagabundo [1.1K]

Answer:

ball B

Explanation:

6 0
3 years ago
Gaseous methane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 9.6 g of methane is
lianna [129]

Answer:

21.6 g

Explanation:

The reaction that takes place is:

  • CH₄ + 2O₂ → CO₂ + 2H₂O

First we<u> convert the given masses of both reactants into moles</u>, using their <em>respective molar masses</em>:

  • 9.6 g CH₄ ÷ 16 g/mol = 0.6 mol CH₄
  • 64.9 g O₂ ÷ 32 g/mol = 2.03 mol O₂

0.6 moles of CH₄ would react completely with (2 * 0.6) 1.2 moles of O₂. As there are more O₂ moles than required, O₂ is the reactant in excess and CH₄ is the limiting reactant.

Now we <u>calculate how many moles of water are produced</u>, using the <em>number of moles of the limiting reactant</em>:

  • 0.6 mol CH₄ * \frac{2molH_2O}{1molCH_4} = 1.2 mol H₂O

Finally we<u> convert 1.2 moles of water into grams</u>, using its <em>molar mass</em>:

  • 1.2 mol * 18 g/mol = 21.6 g
4 0
3 years ago
_Cuo +H, → _Cu + _H,0
Elena-2011 [213]
<h3>Answer:</h3>

CuO(s) + H₂(g) →  Cu(s) + H₂O(l)

<h3>Explanation:</h3>
  • Assuming the reaction is the reduction of CuO by H₂
  • Then the balanced equation for the reaction is;

CuO(s) + H₂(g) →  Cu(s) + H₂O(l)

  • The equation shows the reducing property of hydrogen gas, such that hydrogen reduces metal oxides such as copper(ii)oxide to the respective metals.
  • The law of conservation requires chemical equations to be balanced so as the mass of reactants will be equal to that of products.
  • In this case; there is 1 copper atom, 1 oxygen atom and 2 hydrogen atoms on both side of the equation and thus the equation is balanced.

3 0
3 years ago
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