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3 years ago

Solve y = x^2 - 18 for x.

Mathematics

1 answer:

viva [34]3 years ago

3 0

Answer:

x = √y+18

Step-by-step explanation:

Given

$y = x^2-18$

In order to solve the equation for x, we have to isolate x on one side of the equation

So,

$y+18 = x^2 -18 + 18\\y + 18 = x^2$

We have to find the value for x, so taking square root on both sides

$\sqrt{x^2} = \sqrt{y+18}$

Solving the squre root

x = $x = \sqrt{y + 18}$

Hence,

x = √y+18 is the correct answer ..

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Plz Help!!!!!!!!!!!!!!!!!1

SashulF [63]

B- bc parentheses () = are used to tell one that there’s no endpoint and brackets [] are used to indicate an endpoint :)))

8 0

3 years ago

Kay added 253 + 14 and got a sum of 393. What did she do wrong? Check all that apply.

SashulF [63]

Answer:

She did not correctly add up the numbers

Step-by-step explanation:

253 + 14 = 267

3 0

3 years ago

Assume that a cross is made between a heterozygous tall pea plant and a homozygous short pea plant. Fifty offspring are produced

Butoxors [25]

Answer:

1) $\chi^2 = \frac{(30-25)^2}{25} +\frac{(20-25)^2}{25} =1 +1 =2$

2) $df = c-1 = 2-1$

Where c represent the number of categories c=2

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Tall =30 , Short =20

We need to conduct a chi square test in order to check the following hypothesis:

H0: The deviations from a 1:1 ratio (25 tall and 25 short) are due to chance.

H1: The deviations from a 1:1 ratio (25 tall and 25 short) are NOT due to chance.

Part 1

So then we know that the expected values would be 25 for each case

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

And if we replace we got:

$\chi^2 = \frac{(30-25)^2}{25} +\frac{(20-25)^2}{25} =1 +1 =2$

Part 2

For this case the degreed of freedom are given by:

$df = c-1 = 2-1$

Where c represent the number of categories c=2

And we can calculate the p value given by:

$p_v = P(\chi^2_{1} >2)=0.157$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(2,1,TRUE)"

7 0

3 years ago

A parking lot is 100 yards long what is the length off 3/4if the parking lot

andriy [413]

I think you mean:
A parking lot is 100 yards long. What is the length of 3/4 of the parking lot?

3/4 * 100 Mathematical Expression.

3/1 * 25 Simplify.

75 Multiply.

Final Answer: 75 yards long

4 0

3 years ago

Suppose that the demand Q^Dand supply Q^Sfor maize meal in Kimberley is given by p=120-0.7Q^Dand p=3+0.2Q^S where the quantity i

bixtya [17]

Answer:

20 rands/kg

130,000 kg

Step-by-step explanation:

The equilibrium quantity and price are the solution to the system of equations ...

p = 120 -0.7q

p = 3 + 0.2q

Setting these equal, we get ...

0.2q +3 = p = -0.7q +120

0.9q = 117 . . . . . . . add 0.7q-3 to both sides

q = 117/0.9 = 130

p = 3 +0.2·130 = 29

The equilibrium price of maize meal is 29 rands per kg; the market equilibrium quantity is 130,000 kg.

8 0

3 years ago