Get them to have a common denominator. 100 is the common denominator, so change 7/10 and 3/5 to have a denominator of 100. 7/10=70/100 and 3/5=60/100. So from least to greatest it will go 8/100, 3/5, 7/10.
The Prove that two non-zero vectors are collinear if and only if one vector is a scalar multiple of the other is given below.
<h3>What are the proves?</h3>
1. To know collinear vectors:
∧ ⁻a ║ ⁻a
If ⁻b = ∧ ⁻a
then |⁻b| = |∧ ⁻a|
So one can say that line ⁻b and ⁻a are collinear.
2. If ⁻a and ⁻b are collinear
Assuming |b| length is 'μ' times of |⁻a |
Then | 'μ' ⁻a| = | 'μ' ⁻a|
So ⁻b = 'μ' ⁻a
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Answer:
0.8
Step-by-step explanation:
i believe it would be 56/7000 and you multiply your answer 0.008 by 100 so 0.8 had a mild reaction
You can divide. i believe
Answer:
f(-3) = 41
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = -12x + 5
f(-3) is x = -3
<u>Step 2: Evaluate</u>
- Substitute in <em>x</em>: f(-3) = -12(-3) + 5
- Multiply: f(-3) = 36 + 5
- Add: f(-3) = 41
