Question

HOW WOULD I DO THIS??????????????

Answer 1

Answer:

i) $=3x^2+19x+6$

ii) (f-g)(x)=2x-5

iii) (f+g)(-1)=3

Step-by-step explanation:

f(x)=3x+1

g(x)=x+6

we are asked to determine

i) (f.g)(x) = f(x).g(x)

$=(3x+1)(x+6)$

$=3xx+3x\cdot \:6+1\cdot \:x+1\cdot \:6$

$=3xx+3\cdot \:6x+1\cdot \:x+1\cdot \:6$

$=3x^2+19x+6$

ii) (f-g)(x)=f(x)-g(x)

=(3x+1)-(x+6)

=3x+1-x-6

(f-g)(x)=2x-5

iii) (f+g)(x) = f(x) + g(x)

= (3x+1)+(x+6)

= 3x+x+1+6

(f+g)(x)=4x+7

(f+g)(-1)=4(-1)+7

=-4+7

(f+g)(-1)=3