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OLEGan [10]
4 years ago
5

3-74. Mentally calculate the following products.  Use the rule for decimal multiplication to write an equation in which the deci

mal point is written in the correct location.  Homework Help ✎ (−0.04)(−0.1)  (0.03)(−0.02)  (0.7)(0.4)  Stacey said, “Stephanie, look at my answer to the last problem, 0.7 · 0.4 = 0.28.  Usually when I multiply, I get a bigger answer than the numbers I start with.  Twenty-eight hundredths, 0.28, is less than either 0.4 or 0.7.  I must have made a mistake.” Stephanie responded, “Well, one half times one half is one fourth, and one fourth is less then one half.  I think when you multiply by a fraction or decimal less than one, you get less than you started with.” Write a sentence or two about who you think is correct and why.
Mathematics
2 answers:
Colt1911 [192]4 years ago
5 0
Stephanie is correct, because when you multiply a number by a number less than 1 it becomes smaller.
ale4655 [162]4 years ago
3 0
I think Stephine is correct, because we must do it like this:
   2

   0.7
x 0.4
-----------
   0.28
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1. Given points A(3, -5) and B(19, -1), find the coordinates of point C that sit 3/8 of the way along line AB, closer to A than
zaharov [31]

1. C(x, y) = (7.3, –3.9)

2. C(x, y) = (17, –1.5)

Solution:

Question 1:

Let the points are A(3, –5) and B(19, –1).

C is the point that on the segment AB in the fraction \frac{3}{8}.

Point divides segment in the ratio formula:

$C(x, y)=\left(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n}\right)

Here, x_1=3, y_1=-5, x_2=19, y_2=-1 and m = 3, n = 8

$C(x, y)=\left(\frac{3\times19+8\times3}{3+8} , \frac{3\times(-1)+8\times(-5)}{3+8}\right)

           $=\left(\frac{57+24}{11} , \frac{-3-40}{11}\right)

           $=\left(\frac{81}{11} , \frac{-43}{11}\right)

C(x, y) = (7.3, –3.9)

Question 2:

Let the points are A(3, –5) and B(19, –1).

C is the point that on the segment AB in the fraction \frac{3}{8}.

Point divides segment in the ratio formula:

$C(x, y)=\left(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n}\right)

Here, x_1=3, y_1=-5, x_2=19, y_2=-1 and m = 7, n = 1

$C(x, y)=\left(\frac{7\times19+1\times3}{7+1} , \frac{7\times(-1)+1\times(-5)}{7+1}\right)

           $=\left(\frac{133+3}{8} , \frac{-7-5}{8}\right)

           $=\left(\frac{136}{8} , \frac{-12}{8}\right)

C(x, y) = (17, –1.5)

8 0
3 years ago
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