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3 years ago

I need help with that ASAP

Mathematics

1 answer:

r-ruslan [8.4K]3 years ago

4 0

Answer:

Step-by-step explanation:

Okay so the ∠2 = 40deg. That means ∠2 + ∠6 = 180

∠6 = 180 - 140

Same goes for ∠1, ∠1 + ∠2 = 180, ∠1 = 180 - 40 = 140

∠1 + ∠6 = 140 + 140 = 280degrees = Ans D

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The null and alternative hypotheses are given. Determine whether the hypothesis test is left-tailed, right-tailed, or two-tailed

NNADVOKAT [17]

Correct clear question is;

The null and alternative hypotheses are given. Determine whether the hypothesis test is left-tailed, right-tailed, or two-tailed. What parameter is being tested? H_0: μ = 5 H_1: μ ≠ 5

Is the hypothesis test left-tailed, right tailed, or two tailed? A Left tailed B Right tailed C Two tailed

What parameter is being used? A population proportion B population mean C standard deviation

Answer:

A) C - Two tailed hypothesis

B) B - Population mean

Step-by-step explanation:

We are given the hypotheses to be;. Null Hypothesis; H_0: μ = 5

Alternative hypothesis; H_1: μ ≠ 5

From the alternative hypothesis, we can see that the critical area of distribution of the parameter being tested could either be less than 5 or greater than 5 due to the not equal to sign. This means it could either be left tailed or right tailed. Thus, it is a two tailed hypothesis.

From the hypothesis, we see that the symbol μ is being used.

In statistics, μ is generally used as a symbol to denote population mean.

Thus, parameter being used/tested is population mean

4 0

3 years ago

Please help me I stink at math ☹️

Greeley [361]

4) Part A draw half of a trapezoid
Part B say that they are four sided shapes with a nintey degree angle
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3 0

3 years ago

Read 2 more answers

Amy and rob each improve thier yards by pmanting rose bushes and ivy. They brought thier supplies from the same store. Amy spent

Rzqust [24]

Answer: cost of 1 pot of ivy = $12

Cost of 1 rose bush =$ 10

Step-by-step explanation:

Step 1

Let rose bushes be represented as r

and pot of ivy be represented as p

such that Amy who spent 82 dollars on 7 rose bushes and 1 pot of ivy can be expressed as

7 r + p = 82----- eqn 1

Rob who spent 74 on 5 rose bushes and 2 pots of ivy can be expressed as

5r +2 p = 74----- eqn 2

Step 2

Solving

7 r + p = 82----- eqn 1

5r +2 p = 74----- eqn 2

By elimination method Multiply eqn 1 by 5 and eqn 2 by 7

35r+ 5p= 410--- eqn 3

35r+ 14p =518--- eqn 4

Subtracting eqn 4 from eqn 3

9p = 108

p = 108/9

p=12

p = pot of ivy = $12

therefore rose bush wll be ( from equation 1)

7r+ p= 82

7r=82-12

7r= 70 r= 70/7

r= rose bush =$ 10

5 0

3 years ago

Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th

grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

$S = \{1,1,2,2,2,3\}$

And the probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{6}$

$P(1) = \frac{1}{3}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{6}$

$P(2) = \frac{1}{2}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{6}$

P(Odd Number) is then calculated as:

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{6}$

$P(Odd\ Number) = \frac{3}{6}$

$P(Odd\ Number) = \frac{1}{2}$

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

$S = \{1,1,2,2,2,3,3\}$

The probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{7}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{7}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{7}$

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{7}$

$P(Odd\ Number) = \frac{3}{7}$

Comparing P(Odd Number) before and after

$P(Odd\ Number) = \frac{1}{2}$ --- Before

$P(Odd\ Number) = \frac{3}{7}$ --- After

<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>

7 0

3 years ago

Pls help!<br><br> The question is in the picture below

Sophie [7]

You divide the shape into as many shapes as you want, and then multiply then all and add!

6 0

3 years ago

Read 2 more answers