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Leni [432]
3 years ago
9

At a DBE lecture of 100 students, there are 29 women and 23 men. Out of these students, 4 are teachers and 24 are either men or

teachers. Find the number of women teachers attending the lecture
.
Mathematics
1 answer:
sukhopar [10]3 years ago
7 0

Answer:

100-29=71

71-23=48

48/2=24

Therefore, 24-4=20

answer =20

Step-by-step explanation:

twenty teachers are the one attending the the lectures

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The constant of proportionality of the given graph is gotten as 4.

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Answer:

a) 0.98% probability that 17 of the 29 people are men.

b) 3.86% probability that the first woman is reached on the 8th call

Step-by-step explanation:

For each person chosen by the agency, there are only two possible outcomes. Either it is a man, or it is a woman. The probability of selecting a man or a women in each trial is independent from other trials. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

(a) What is the probability that 17 of the 29 people are men?

This is P(X = 17) when n = 29, p = 0.78. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 17) = C_{29,17}.(0.78)^{17}.(0.22)^{12} = 0.0098

0.98% probability that 17 of the 29 people are men.

(b) What is the probability that the first woman is reached on the 8th call?

On the first 7 trials, all men, each with a 78% probability.

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