Hello :
<span> the axis of symmetry is the line for equation : x = 2
the </span><span>vertex is the point : A (2 , 4)</span>
Answer:
We have the next relation:
A = (b*d)/c
because we have direct variation with b and d, but inversely variation with c.
Now, if we have 3d instead of d, we have:
A' = (b*(3d))/c
now, we want A' = A. If b,c, and d are the same in both equations, we have that:
3bd/c = b*d/c
this will only be true if b or/and d are equal to 0.
If d remains unchanged, and we can play with the other two variables we have:
3b'd/c' = bd/c
3b'/c' = b/c
from this we can took that: if c' = c, then b' = b/3, and if b = b', then c' = 3c.
Of course, there are other infinitely large possible combinations that are also a solution for this problem where neither b' = b or c' = c
Answer:
B
Step-by-step explanation:
Let me know if you need an explanation.
Answer:
Step-by-step explanation:
1. a). Hypotenuse² = (Leg 1)² + (Leg 2)²
h² = 10² + 24²
h = √676
h = 26
(b). Hypotenuse² = (Leg 1)² + (Leg 2)²
(25)² = (15)² + (leg 2)²
Leg 2 = √(625 - 225)
= √400
= 20
(c). Hypotenuse² = (Leg 1)² + (Leg 2)²
h² = 4² + 6²
h = √(16 + 36)
h = √52
h = 2√13
(d). Hypotenuse² = (Leg 1)² + (Leg 2)²
(14)² = (Leg 1)² + 7²
Leg 1 = √(196 - 49)
= √147
= 7√3
2). Hypotenuse² = (Leg 1)² + (Leg 2)²
Leg 1 = leg 2 = 7 units [Since, triangle is an isosceles triangle]
h² = 7² + 7²
h = √98
h = 7√2
Option (1) is the correct option.
3). Hypotenuse² = (Leg 1)² + (Leg 2)²
(26)² = (Leg 1)² + (10)²
Leg 1 = √(676 - 100) = 24
Area of a right triangle = 
= 
= 120 square units
Option (3) is the correct option.