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katrin [286]
3 years ago
13

Sec s = 1.6948

Mathematics
1 answer:
Anastaziya [24]3 years ago
5 0
That'd be true only if the value of "s" is the exact same one for both
namely  if sec(s) = cos(s)
then solving for "s"
thus

\bf sec(s)=cos(s)\qquad but\implies sec(\theta)=\cfrac{1}{cos(\theta)}
\\\\\\
thus\cfrac{1}{cos(s)}=cos(s)\implies 1=cos^2(s)\implies \pm \sqrt{1}=cos(s)
\\\\\\
\pm 1=cos(s)\impliedby \textit{now taking }cos^{-1}\textit{ to both sides}
\\\\\\
cos^{-1}(\pm 1)=cos^{-1}[cos(s)]\implies cos^{-1}(\pm 1)=\measuredangle s
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If the length of the side of a square is 6 cm,then the area will be equal to ________
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What is the area of this composite shape?
ankoles [38]

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<em><u>A. 132 units² </u></em>

<em><u></u></em>

Step-by-step explanation:

The figure has already been broken into chunks, so there is no need to break it up any further.

I'll start with the top left triangle,

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Following this formula, we take the height, 4, and multiply it by the base, 6.

4 x 6 = 24.

Now, we divide the product by 2:

24 / 2 = <em><u>12</u></em>.

We now have the area for the triangle, it is time to move onto the second.

To find the height of the larger triangle, we add 4 and 4 together, giving us 8. To find the base, we subtract 6 from 15, giving us 9.

Now we multiply 8 and 9 together, then divide by 2

8 x 9 = 72

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Now that we've found the area for both triangles, it is time to find the area of the rectangles.

Formula for finding the area of quadrilaterals such as rectangles and squares: <em>L x W</em>

I'll start with the smaller rectangle underneath the top left triangle:

6 x 4 = <em><u>24</u></em>

Now, I'll move onto the bottom rectangle:

15 x 4 = <em><u>60</u></em>

<em><u /></em>

We have the areas of all the shapes in this figure, all we have left to do is to <u>add them together</u>:

60 + 24 + 36 + 12 = <u>132 units²</u>

<u></u>

<u>132 units² will be your answer.</u>

<u></u>

<h2>I hope this helps!</h2>
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