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Alex
3 years ago
10

What digits can be in the ones place of a number that has five as the factor

Mathematics
1 answer:
UNO [17]3 years ago
8 0
Only 0 and 5. Proof:
5: 5,10,15,20,25,30,35,40,45...
Also 100,105,110,115...
It keeps going on.
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Use the Trapezoidal Rule, the Midpoint Rule, and Simpson's Rule to approximate the given integral with the specified value of n.
Sunny_sXe [5.5K]

Answer:

  1. -1392.09
  2. -1744.43
  3. -1636.41

Step-by-step explanation:

using the given integral

calculate:  Δx = (12-0) / 8 = 3/2

Xo = 0,   f(x) = x^3sin(x)

X1 = 3/2 ,   X2 = 3, X3 = 9/2,  X4 = 6,  X5 = 15/2,  X6 = 9,  X7 = 21/2,  X8 = 12

Inputting the given values into the Trapezoid rule, midpoint rule and Simpson's rule to approximate the given integral with the specified value of n = 8

8 0
3 years ago
Eric reflected parallelogram ABCD across the x-axis. If angle A is 125° and angle B is 55°, what is the degree measurement of an
Sindrei [870]

Answer:

The measure of angle A' is 125°

Step-by-step explanation:

we know that

Under reflection, lengths, areas and angles do not change but orientation does

therefore

If angle A is 125°

then

after the reflection

m∠A=m∠A'

therefore

The measure of angle A' is 125°

7 0
3 years ago
Please look at the image and answer it correctly
Vaselesa [24]

Answer:

Its B

Hope it helps!......

8 0
3 years ago
Read 2 more answers
Solve the equation by completing the square. -9n^2+79+=-18n
poizon [28]
Hello,
-9n²+79=-18n
==>9n²-18n-79=0
==>9(n²-2n+1-1)-79=0
==>9(n-1)²-88=0
==>[3(n-1)-2√22][3(n-1)+2√22]=0
==>3(n-1)=2√22 or 3(n-1)=-2√22
==>n-1=2/3*√22 or n-1=-2/3*√22
==>n=1+2/3*√22 or n=1-2/3*√22



6 0
3 years ago
X^2 - 72 = 6x<br> how to complete the square?
muminat

Answer:

x = 12 and x = -6

Step-by-step explanation:

First subtract 6x on both sides to get a 2nd degree polynomial equal to zero:

x^2-6x-72=0

To complete the square, the formula is to divide 'b' by 2 and square the result. The general form for a 2nd degree polynomial of the variable 'x' is as follows:

ax^2+bx+c=0

For your case, b = 6. Therefore, the term that must be added and subtracted to our equation is:

(6/2)^2=3^2=9

Add and subtract 9 to our equation to get:

x^2-6x+9-9-72=0

The first three terms form a perfect square, we have:

(x^2-6x+9)-9-72=0

(x^2-6x+9)-81=0

What multiplies to equal 9 but adds to equal -6? That would be -3 and -3. Therefore:

(x-3)^2-81=0

Add 81 to both sides to get:

(x-3)^2=81

We want to take the square root, but recall a square root has a positive and negative branch. Therefore we have two solutions:

x-3=9

x-3=-9

x=12

x=-6

3 0
3 years ago
Read 2 more answers
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