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Sloan [31]
3 years ago
12

Use the Trapezoidal Rule, the Midpoint Rule, and Simpson's Rule to approximate the given integral with the specified value of n.

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
8 0

Answer:

  1. -1392.09
  2. -1744.43
  3. -1636.41

Step-by-step explanation:

using the given integral

calculate:  Δx = (12-0) / 8 = 3/2

Xo = 0,   f(x) = x^3sin(x)

X1 = 3/2 ,   X2 = 3, X3 = 9/2,  X4 = 6,  X5 = 15/2,  X6 = 9,  X7 = 21/2,  X8 = 12

Inputting the given values into the Trapezoid rule, midpoint rule and Simpson's rule to approximate the given integral with the specified value of n = 8

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Please help I will give brainliest IF IT IS CORRECT
Andreyy89

Answer:

third graph and (3, -1)

Step-by-step explanation:

y = 2/3x - 3

y = -2x + 5

2/3x - 3 = -2x + 5

2 2/3x = 8

8/3x = 8

8x = 24

x = 3

find 'y'

y = -2(3) + 5

y = -1

The third graph is correct because it shows both a line intersecting the y-axis at -3 and the negative slope line is crossing at +5

5 0
2 years ago
The Copy Shop has made 20 copies of a document for you. Since the defective rate is 0.1, you think there may be some defective c
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Answer:

Binomial

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

Step-by-step explanation:

For each copy of the document, there are only two possible outcomes. Either it is defective, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem

Of the 20 copies, 2 are defective, so p = \frac{2}{20} = 0.1.

What is the probability that you will encounter neither of the defective copies among the 10 you examine?

This is P(X = 0) when n = 10.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.3487

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

8 0
3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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oee [108]

Answer:  The graph is attached.

Step-by-step explanation:  The given functions whose graphs are to be compared are as follows:

y=\dfrac{1}{x},~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)\\\\\\y=\dfrac{5}{x}+6.~~~~~~~~~~~~~~~~~~~~~~~~~(B)

In the attached figure, the graphs of both (A) and (B) are shown. We can easily see see from there, the shapes of both the graphs are same.

But, at x = 0, y = ∞ and at x = ∞, y = 0 in graph (A).

At  x = 0, y = ∞ and at x = ∞, y = 6 in graph (B).

Thus, the comparison can be seen in the figure very clearly.

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Answer:

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Step-by-step explanation:

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