if the problem is (5x^4y^3)^2 divided by 9
5^2 = 25
4*2 =8
3*2 =6
so you get (25x^8y^6)/9
if that isn't how the equation was supposed to be written let me know and I will edit my answer.
9514 1404 393
Answer:
m^2 = 35/9
Step-by-step explanation:
The line will be tangent to the ellipse where there is one point of intersection between the line and the ellipse. We can find that case by looking at the discriminant of the quadratic.
x^2 +9(mx +2)^2 = 1
x^2 +9(m^2x^2 +4mx +4) = 1
(9m^2 +1)x^2+36mx +35 = 0 . . . . subtract 1, collect terms
__
Then the discriminant is ...
(36m)^2 -4(9m^2 +1)(35)
We want it to be zero, so we have ...
1296m^2 -1260m^2 -140 = 0 . . . . eliminate parentheses
36m^2 = 140 . . . . . . . . . . . . . . . add 140
m^2 = 140/36 . . . . . . . . . . . . divide by 36
m^2 = 35/9
we have: ∠P + ∠Q + ∠R = 180°
<=> (4x – 14)º + (5x + 6)° + (x - 2)° = 180°
<=> 4x – 14 + 5x + 6 + x - 2 = 180°
<=> 10x - 10 = 180°
<=> 10x = 190
<=> x = 19°
So: ∠R = (x - 2)° = (19 - 2)° = 17°
ok done. Thank to me :>
Answer: 119
Step-by-step explanation: if it’s 1:7,
then you’d have to do 17x7