Answer:
20π ft
Step-by-step explanation:
To find the circumference of the circle given its area, first find its radius.
Substitute given area into the formula:
100π= πr²
Divide both sides by π:
100= r²
Square root both sides:
r= 10 ft
Since we have found the value of the radius, we can substitute r= 10 into the formula above to find the circumference.
Circumference of circle
= 2(π)(10)
= 20π ft
4 x 7 divided by 9. Set 7 equal to 7/1. Now you have 4/9 x 7/1. Multiply numerators and denominators
(22 - 3) / (4 +1) = 19/5
slope = 19/5
Answer:
124
Step-by-step explanation:
To find the surface area, we add the area from all faces or the prism.
the first face, we can put 8 times 2.5, which is 20. There are two of these faces, so we have 40 in our area so far.
next the other face. 4 times 2.5 is 10, and there are two of these faces. 60 in out area.
now the top and bottom faces. 8 times 4 is 32. there are two of these faces, and 60 +64 = 124
We can start solving this problem by first identifying what the elements of the sets really are.
R is composed of real numbers. This means that all numbers, whether rational or not, are included in this set.
Z is composed of integers. Integers include all negative and positive numbers as well as zero (it is essentially a set of whole numbers as well as their negated values).
W on the other hand has 0,1,2, and onward as its elements. These numbers are known as whole numbers.
W ⊂ Z: TRUE. As mentioned earlier, Z includes all whole numbers thus W is a subset of it.
R ⊂ W: FALSE. Not all real numbers are whole numbers. Whole numbers must be rational and expressed without fractions. Some real numbers do not meet this criteria.
0 ∈ Z: TRUE. Zero is indeed an integer thus it is an element of Z.
∅ ⊂ R: TRUE. A null set is a subset of R, and in fact every set in general. There are no elements in a null set thus making it automatically a subset of any non-empty set by definition (since NONE of its elements are not an element of R).
{0,1,2,...} ⊆ W: TRUE. The set on the left is exactly what is defined on the problem statement for W. (The bar below the subset symbol just means that the subset is not strict, therefore the set on the left can be equal to the set on the right. Without it, the statement would be false since a strict subset requires that the two sets should not be equal).
-2 ∈ W: FALSE. W is just composed of whole numbers and not of its negated counterparts.
