We can use elimination for these set of systems.
First, we need to set up our variables.
Belts=b
Hats=h
Now, the situation is 6 belts and 8 hats for $140. The situation after is 9 belts and 6 hats for $132.
Let’s set up our system of equations.
6b+8h=140
9b+6h=132
We need to eliminate a variable. Since b has coefficients of 6 and 9, we can easily eliminate b by multiplying the top equation by 3 and the bottom by -2.
18b+24h=420
-18b-12h=-264
Now let’s add.
12h=156
Let’s divide to get h by itself.
156/12=13=h
So a hat costs $13. We need to put in 13 for one of the equations so we can find the cost of a belt.
9b+6(13)=132
9b+78=132
We need b by itself.
9b=54
54/9=6
Belts are $6
We can also use the first equation to check our answers.
6(6)+8(13)
36+104
140.
So, the price of a belt is $6 while the price of a hat is $13.
C. The answer is C because the total amount of students is 14, and there are 4 boys, which makes the ratio 4 boys to 14 students in total. 4 and 14 are both divisable by 2, so divide 4 to get 2 and divide 14 to get 7. This leaves you with 2 and 7. The ratio would be 2 boys to 7 total students. Hope this helped
<h3>
Answer: 128.74 square meters</h3>
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Explanation:
The area of the garden only (ignore the circular pathway) is approximately
A = pi*r^2
A = 3.14*20^2
A = 1256
The area of the garden plus the path is approximately
A = pi*r^2
A = 3.14*21^2
A = 1384.74
Notie how I added on 1 meter to increase the radius to 21
Subtract the two circle areas to get the area of the circular ring.
1384.74 - 1256 = 128.74
The units for all of the areas mentioned are "square meters".
We are given with two dimensions of a can of paint in which I assume is a cylinder: 14 cm diameter and 16 cm height. In this case, the formula to be used is V = pi*d^2*h/4. substituting the given data above, V = pi*14^2*h/16 equal to 2462 cm^3. units must be consistent throughout to achieve the right answer.
Answer:
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Step-by-step explanation:
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