Answer:
D(1, 2) → D'(2, 7)
E(-3, -5) → E'(-10, 0)
F(4, -1) → F'(11, 4)
Step-by-step explanation:
D(1, 2) → D' ________
Translate image (3x - 1, y + 5)
(1, 2), x = 1 and y = 2
3x - 1 = 3(1) - 1 = 3 - 1 = 2
y + 5 = (2) + 5 = 7
E(-3, -5) → E' ________
(-3, -5), x = -3 and y = -5
3x - 1 = 3(-3) - 1 = -9 - 1 = -10
y + 5 = (-5) + 5 = 0
F(4, -1) → F' ________
(4, -1), x = 4 and y = -1
3x - 1 = 3(4) - 1 = 12 - 1 = 11
y + 5 = (-1) + 5 = 4
Answer:
A racer has just completed his first lap at a speed of 198m/s. Now his speed decrease or he decelerateted at 195m/s after 2s of his completion of first lap, as soon as he saw a curve path(line segment R). He then moved at a constant speed of 195m/s for the next 2s(line segment s). Then the race track after 4s of the completion of first lap was straight, so the racer accelerated to 200m/s within 2s( line segment T) and traveled at a constant speed for the next 6s( line segment U). After 12s from the first lap completion, he immediately saw a curve track, so he decelerateted to the speed of 194m/s within 3s( line segment V).
Hope it helped.
please mark brainliest
Answer:
a
Step-by-step explanation:
=3a + a + 2a - 5a
=4a - 3a
= a
hope it helps u tate!
The answer is #2 you’re welcome
the distance between points is:
d = 7.8 units
d = root ((x2-x1) ^ 2 + (y2-y1) ^ 2)
The ordered pairs are:
(x1, y1) = (- 3, -2)
(x2, y2) = (2,4)
By applying the formula we have:
d = root ((2 - (- 3)) ^ 2 + (4 - (- 2)) ^ 2)
d = root (61)
d = 7.8
