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Lapatulllka [165]
4 years ago
11

I need help asap please help me quick

Mathematics
2 answers:
grigory [225]4 years ago
6 0

Answer:

C. 3(x+5)

Hope this helps

tresset_1 [31]4 years ago
3 0

Answer:

C. 3(x+5)

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

gfdgdfgfdgdfgfdgfd

4 0
3 years ago
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Please help.<br> Explain please.
Sunny_sXe [5.5K]
When n = 1, 2(1) + 1 = 3

When n = 2, 2(2) + 1 = 5

When n = 3, 2(3) + 1 = 7

When n = 4, 2(4) + 1 = 9

When n = 5, 2(5) + 1 = 11

Sum = 3 + 5 + 7 + 9 + 11 = 35

----------------------------------------------------
Answer: 35
----------------------------------------------------
4 0
3 years ago
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Se tiene un rectángulo cuya base mide el doble que su altura y su área es 12
irina [24]

Answer:

Part 1) The perimeter is  P=6\sqrt{6}\ cm

Part 2) The diagonal is d=\sqrt{30}\ cm

Step-by-step explanation:

<u><em>The question in English is</em></u>

You have a rectangle whose base is twice the height and its area is 12

square centimeters. Calculate the perimeter of the rectangle and its diagonal

step 1

Find the dimensions of rectangle

we know that

The area of rectangle is equal to

A=bh

A=12\ cm^2

so

bh=12 ----> equation A

The base is twice the height

so

b=2h ----> equation B

substitute equation B in equation A

(2h)h=12\\2h^2=12\\h^2=6\\h=\sqrt{6}\ cm

Find the value of b

b=2\sqrt{6}\ cm

step 2

Find the perimeter of rectangle

The perimeter is given by

P=2(b+h)

substitute

P=2(2\sqrt{6}+\sqrt{6})\\P=6\sqrt{6}\ cm

step 3

Find the diagonal of rectangle

Applying the Pythagorean Theorem

d^2=b^2+h^2

substitute

d^2=(2\sqrt{6})^2+(\sqrt{6})^2

d^2=30

d=\sqrt{30}\ cm

3 0
3 years ago
If one real number is equal to a second real number, and the second real number is equal to a third real number, then the first
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Answer: In particular, let’s focus our attention on the behavior of each graph at and around . 2 and x= -1 for x < 2. There are open circles at both endpoints (2, 1) and (-2, 1). The third is h (x) = 1 / (x-2)^2, in which the function curves asymptotically towards y=0 and x=2 in quadrants one and two."

Step-by-step explanation: I think this is the problem ur on

8 0
3 years ago
jackie is making a beaded bracelet. The bracelet will have no more than 12 beads. 1/3 of the beads on the bracelet will be green
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Since there could be no more than 12 the multiples of 1/3 untill a denominator of 12 are 2/6 3/9 and 4/12
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3 years ago
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