Answer:1, 2, and 4
Explanation:
covalent bonds are not ionic. the elements SHARE electrons
Which of the following are properties of compounds formed by covalent bonding (Select all that apply)
1. When you dissolve an covalent compound in water, the solution does not conduct electricity.
2. Covalent compounds often have lower melting points than ionic compounds.
3. When you dissolve an covalent compound in water, the solution conducts electricity.
4. Covalent compounds form when combining two or more nonmetal atoms.
5. Covalent compounds form when combining a two metal atoms.
6. Covalent compounds form when combining a metal atom with a nonmetal atom.
Answer:
See the answer below
Explanation:
From the original equation in the image, the mole ratio of C:CO2:CO is 1:1:2. This means that for every 1 mole of C and CO2, 2 moles of CO would be produced.
Now, looking at the simulation below the equation of the reaction, 3 moles of C and 8 moles of CO2 were supplied as input. Applying this to the original equation of reaction, C seems to be a limiting reagent for the reaction because the ratio of C to CO2 should 1:1.
Hence, taking all the 3 moles of C available means that only 3 moles out of the available 8 for CO2 would be needed. 3 moles c and 3 moles CO2 means that 6 moles CO would be produced (remember that the ratio remains 1:1:3 for C, CO2, and CO). This means that 5 moles CO2 would be leftover.
<em>In other words, all the 3 moles C would be consumed, 3 out of 8 moles CO2 would be consumed, and 6 moles CO would be produced while 5 moles CO2 would be leftover. </em>
Answer:
Anode is the positively charged electrode which has the following characteristics:
1) Electrons leave anode to enter to the cathode by the battery.
2) Negatively charged ions are attracted towards cathode.
3) It is connected to the positive terminal of the battery.
Answer:
0.095 moles of O₂ are left over.
Explanation:
First of all, state the balanced reaction:
2NO + O₂ → 2NO₂
We determine moles of each reactant:
20.2 g . 1mol / 30g = 0.673 moles of NO
13.8g . 1mol / 32g = 0.431 moles of oxygen
Oxygen is the excess reactant. Let's see.
For 2 moles of NO I need 1 mol of O₂
Then, for 0.673 moles of NO I may use (0.673 .1) /2 = 0.336 moles
I have 0.431 moles of O₂ and I only need 0.336 mol. According to reaction, stoichiometry is 2:1.
In conclussion, the moles of excess reactant that will be left over:
0.431 - 0.336 = 0.095 moles
I know it is far late but the atom number remains the same
