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AnnyKZ [126]
3 years ago
11

2x=45-3xs simplify?

Mathematics
1 answer:
Lelu [443]3 years ago
8 0
2x=45-3xs

1. Add 3xs to both sides

2x+3xs=45

2. Factor out the common term X

X(2+3s)=45

3. Divide both sides by 2+3s

X= 45/2+3s

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The mean yearly rainfall in Sydney, Australia, is about 134 mm and the standard deviation is about 66 mm ("Annual maximums of,"
svetlana [45]

Answer:

At least 202.44 mm in the top 15%.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 134, \sigma = 66

How many yearly mm of rainfall would there be in the top 15%?

At least X mm.

X is the 100-15 = 85th percentile, which is X when Z has a pvalue of 0.85. So X when Z = 1.037.

Z = \frac{X - \mu}{\sigma}

1.037 = \frac{X - 134}{66}

X - 134 = 66*1.037

X = 202.44

At least 202.44 mm in the top 15%.

5 0
3 years ago
Reposting becuase it want let me edit my last one and somebody spam answered it.
harkovskaia [24]

Answer:

5

5Step-by-step explanation:

If you use the distance formula you can solve it pretty easily. The distance formula is:

d = \sqrt{(x2 - x1)^2 + (y2 - y1)^2} \\

The two points you want are A and D. A is (-1, -4) and D is (3, -1). Plug that into the formula...

d = \sqrt{(3 - (-1))^2 + (-1 - (-4))^2}

d = \sqrt{4^2 + 3^2}

d = \sqrt{16 + 9}

d = \sqrt{25}

5

I can solve it in a different way if you want me to.

8 0
3 years ago
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