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Gnom [1K]
3 years ago
11

The x-intercepts of a quadratic function are −3 and 5. What is the equation of its axis of symmetry?

Mathematics
1 answer:
Jobisdone [24]3 years ago
3 0

Answer:

x = 1

Step-by-step explanation:

The graph intersects the x-axis at -3 and 5.  The axis of symmetry is precisely halfway between these two points:  (-3 + 5) / 2 = 2 / 2 = 1.

The axis of symmetry is the vertical line x = 1.

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Trigonometry, can anybody help??
WINSTONCH [101]

Answer:

angle B: 39

AC: 7.288

AB: 11.58

(note: you cut off the part about rounding so make sure that it's rounded correctly before you put in your answer)

Step-by-step explanation:

To solve this we will use SOH, CAH, TOA

we have the angle and the one opposite to it which means we can use either SOH or TOA

let's use TOA

tan(51)=(9/x)

x= 7.288

We can now use pahtagaryous theroem to solve for the hyptonouse

we have

9²+7.288²=C²

C=11.58

Finally, to find angle B we will recall that the angles of a triangle must add to 180.

51+90+a=180

a=39

5 0
2 years ago
Urgent help needed fast
Katena32 [7]

Answer:

Below

Step-by-step explanation:

You can use this formula to find the sum of an arithmetic series

     Sn = n / 2 (a1 + an)

You need to find the number of terms in each series before using the formula

     Tn = a + (n - 1) d

a) 53 = 5 + (n - 1) 3

      n = 17

Sn = 17 / 2 (5 + 53)

    = 493

b) 98 = 7 + (n - 1) 7

      n = 14

Sn = 14 / 2 (7 + 98)

   = 735

       

c) -102 = 8 + (n - 1) -5

        n = 23

Sn = 23 / 2 (8 + (-102))

   = - 1081

d) 41/3 = 2/3 + (n - 1) 1

        n = 14

Sn = 14 / 2 (2/3 + 41/3)

    = 301 / 3 or 100 1/3  

Hope this helped! Best of luck <3

7 0
2 years ago
Which triangle is obtuse?
Harrizon [31]

the one wayyy on the top

5 0
3 years ago
Read 2 more answers
Which equation has infinitely many solutions?
Snezhnost [94]

Answer:

Bbbbbbbbbbbbbbbbbbbbbb

4 0
2 years ago
(3x – 1) : (x - 2) = x – 2x (x—4)<br> срочно, сор.
RSB [31]

\frac{3x-1}{x-2}=x-2x(x-4)  \frac{3x-1}{x-2}=x-2x^{2} +8x \\\frac{3x-1}{x-2}=-2x^{2} +9x3x-1= (-2x^{2} +9x)(x-2)\\3x-1= -2x^3+4x^{2} +9x^{2} -18x\\3x-1=-2x^3+13x^{2} -18x\\2x^3 -13x^{2} +18x+3x -1=0\\2x^3 -13x^{2}+21x-1=0\\ x =0.05 /or/x=3.7

ok done. Thank to me :>

6 0
2 years ago
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