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Firlakuza [10]
3 years ago
5

Find h when v=672.12 and r=4

Mathematics
2 answers:
tatiyna3 years ago
5 0
88



Cause I fully don’t know
rodikova [14]3 years ago
5 0
Could you add a picture of the assignment?
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Determine the quotient of 2/5 divided by 3/4.
Stella [2.4K]

Answer:

A- 8/15

Step-by-step explanation:

2/5 ÷ 3/4

= 2 × 4/5 × 3

= 8/15


3 0
3 years ago
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The bakery owner will use both machines to glaze a total of doughnuts. She plans to start both machines at the same time. Based
creativ13 [48]

Answer:

Step-by-step explanation:

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3 years ago
A town has 5000 people in year t = 0. Calculate how long it takes for the population P to double once, twice, and three times, a
UNO [17]

Answer:

Step-by-step explanation:

At the time t = 0, population of the town = 5000

Rate of population increase = 500 per year

Therefore, the equation that will represent the population will be

P_{t}=P_{0}+500t

Where P_{t} = Population after t years

P_{0}= Initial population

t = Time in years

a). For double once the population will be 500×2 = 10000

By plugging in the values in the equation,

10000 = 5000 + 500t

500t = 10000 - 5000

500t = 5000

t = \frac{5000}{500}

t = 10 years

For Double twice,

Population will be = 10000×2 = 20000

Now we plug in the values in the equation again

20000 = 5000 + 500t

500t = 20000 - 5000

500t = 15000

t = \frac{15000}{500}

t = 30 years

For double thrice,

Population of the town = 20000×2 = 40000

Now we plug in the values in the equation,

40000 = 5000 + 500t

500t = 40000 - 5000

500t = 35000

t = \frac{35000}{500}

t = 70 years

b). If the population growth is 5%.

Then the growth will be exponential represented by

T_{n}=T_{0}(1+\frac{r}{100})^{t}

T_{n} = Population after t years

T_{0} = Initial population

t = time in years

For double once,

Population after t years = 10000

10000=5000(1+\frac{5}{100})^{t}

(1.05)^{t}=\frac{10000}{5000}

(1.05)^{t}=2

Take log on both the sides

log(1.05)^{t}=log2

tlog(1.05) = log2

t = \frac{log2}{log1.05}

t = 14.20 years

For double twice,

Population after t years = 20000

20000=5000(1+\frac{5}{100})^{t}

(1.05)^{t}=\frac{20000}{5000}

(1.05)^{t}=4

Take log on both the sides

log(1.05)^{t}=log4

tlog(1.05) = log4

t = \frac{log4}{log1.05}

t = 28.413 years

For double thrice

Population after t years = 40000

40000=5000(1+\frac{5}{100})^{t}

(1.05)^{t}=\frac{40000}{5000}

(1.05)^{t}=8

Take log on both the sides

log(1.05)^{t}=log8

tlog(1.05) = log8

t = \frac{log8}{log1.05}

t = 42.620 years

4 0
3 years ago
The graph shows the relationship between the hours a soccer team practiced after the season started and their total practice tim
Sergio [31]

Answer:

6 hours

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

Let

x ----> the hours a soccer team practiced after the season started

y ----> the  total practice time for the year in hours

we know that

The y-intercept of a linear equation is the value of x when the value of y is equal to zero

In the context of this problem, the y-intercept is the  total practice time before the season began (the value of x is equal to zero)

Looking at the graph

The y-intercept is the point (0,6)

therefore

the  total practice time before the season began is 6 hours

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3 years ago
You toss two coins. what is the probability p that both are tails
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25% or 1/4

1/2 × 1/2 = 1/4
3 0
3 years ago
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