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Answers:</h3>
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Work Shown:
Part 1
Notice how I replaced every x with g(x) in step 2. Then I plugged in g(x) = x^2+6 and simplified.
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Part 2
In step 4, I used the rule (a+b)^2 = a^2+2ab+b^2
In this case, a = sqrt(x-1) and b = 5.
You could also use the box method as a visual way to expand out 
Answer:
Delta Ft = 70*3 - 42*7 = 168 #$
V = 1/2bhl
V / 1/2hl = 1/2bhl / 1/2hl
b = 1/2hlV
We know that the maximum and minimum values of the function y = cos x in the interval [-2π, 2π] are 1 and -1 respectively.
The graph of y = 8 cos x is vertical stretch by a factor of 8 units. Therefore the graph y=cos x, = the maximum and minimum values of the function y = cos x in the interval [-2π, 2π]. So they are 8 and -8 respectively.
max = 8, ∈[−2π,2π]
= Solution
min = −8. ∈[−2π,2π]
Answer:
Ok I can definitely answer this but maybe add a picture or a little problem for us because we can’t answer the question without something to tell us what the question Is about. if you post another one of those with a picture then I will be more than glad to answer it.
