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3 years ago

A video game maker claims that number of glitches in code for their

Mathematics

1 answer:

svet-max [94.6K]3 years ago

5 0

Answer:

The major condition that needs to be satisfied before a t-test is performed that the question satisfies easily is the use of random sampling to obtain sample data.

Step-by-step explanation:

The major conditions necessary to conduct a t-test about a mean include;

- The sample extracted from the population must be extracted using random sampling. That is, the sample must be a random sample of the population.

- The sampling distribution must be normal or approximately normal. This is achievable when the population distribution is normal or approximately normal.

- Each observation in the sample data must have an independent outcome. That is, the outcome/result of each sub-data mustn't depend on one another.

Of the three conditions that need to be satisfied before the conduction of a t-test, the first condition about using a random sampling technique is evidently satisfied.

It is stated in the question that 'A private investigator hired by a competitor takes a random sample of 47 games and tries to determine if there are more than 7 glitches per game'.

Hope this Helps!!!

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Someone please help me on both the questions!!!

bonufazy [111]

Step-by-step explanation:

al nth term:

numerator:

$= {n}^{2}$

denominator:

$= n + 1$

so nth term :

$= \frac{ {n}^{2} }{n + 1}$

b). 1; 11; 27; 49

first difference: 10; 16; 22

second difference :6

formula for 1st difference:3a+b

formula for 2nd difference:2a

Therefore:

2a=6

a=3

3a+b=10

sub in a

3(3)+b=10

9+b=10

b=1

sub into quadratic formula

${an}^{2} + bn + c$

$(3) {(1)}^{2} + (1)(1) + c = 1$

$3(1) + 1 + c = 1$

$3 + 1 + c = 1$

$4 + c = 1$

$c = - 3$

So Tn:

$3 {n }^{2} + 1n - 3$

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2 years ago

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Use matrices to determine the coordinates of the vertices of the rotated figure. with vertices MNP M(-2, 6), N(7,1), and P (4,-3

ioda

Answer:

The coordinate of image triangle is M(-6,-2),N(-1,7) and P(3,4)

Step-by-step explanation:

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3 years ago

Is it possible for an x-intercept and a y-intercept to have no intercept

wel

<span>Not all functions will have intercepts</span>

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3 years ago

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Find an equation of the tangent plane to the given parametric surface at the specified point.

Neko [114]

Answer:

Equation of tangent plane to given parametric equation is:

$\frac{\sqrt{3}}{2}x-\frac{1}{2}y+z=\frac{\pi}{3}$

Step-by-step explanation:

Given equation

$r(u, v)=u cos (v)\hat{i}+u sin (v)\hat{j}+v\hat{k}$ ---(1)

Normal vector tangent to plane is:

$\hat{n} = \hat{r_{u}} \times \hat{r_{v}}\\r_{u}=\frac{\partial r}{\partial u}\\r_{v}=\frac{\partial r}{\partial v}$

$\frac{\partial r}{\partial u} =cos(v)\hat{i}+sin(v)\hat{j}\\\frac{\partial r}{\partial v}=-usin(v)\hat{i}+u cos(v)\hat{j}+\hat{k}$

Normal vector tangent to plane is given by:

$r_{u} \times r_{v} =det\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\cos(v)&sin(v)&0\\-usin(v)&ucos(v)&1\end{array}\right]$

Expanding with first row

$\hat{n} = \hat{i} \begin{vmatrix} sin(v)&0\\ucos(v) &1\end{vmatrix}- \hat{j} \begin{vmatrix} cos(v)&0\\-usin(v) &1\end{vmatrix}+\hat{k} \begin{vmatrix} cos(v)&sin(v)\\-usin(v) &ucos(v)\end{vmatrix}\\\hat{n}=sin(v)\hat{i}-cos(v)\hat{j}+u(cos^{2}v+sin^{2}v)\hat{k}\\\hat{n}=sin(v)\hat{i}-cos(v)\hat{j}+u\hat{k}\\$

at u=5, v =π/3

$=\frac{\sqrt{3} }{2}\hat{i}-\frac{1}{2}\hat{j}+\hat{k}$ ---(2)

at u=5, v =π/3 (1) becomes,

$r(5, \frac{\pi}{3})=5 cos (\frac{\pi}{3})\hat{i}+5sin (\frac{\pi}{3})\hat{j}+\frac{\pi}{3}\hat{k}$

$r(5, \frac{\pi}{3})=5(\frac{1}{2})\hat{i}+5 (\frac{\sqrt{3}}{2})\hat{j}+\frac{\pi}{3}\hat{k}$

$r(5, \frac{\pi}{3})=\frac{5}{2}\hat{i}+(\frac{5\sqrt{3}}{2})\hat{j}+\frac{\pi}{3}\hat{k}$

From above eq coordinates of r₀ can be found as:

$r_{o}=(\frac{5}{2},\frac{5\sqrt{3}}{2},\frac{\pi}{3})$

From (2) coordinates of normal vector can be found as

$n=(\frac{\sqrt{3} }{2},-\frac{1}{2},1)$

Equation of tangent line can be found as:

$(\hat{r}-\hat{r_{o}}).\hat{n}=0\\((x-\frac{5}{2})\hat{i}+(y-\frac{5\sqrt{3}}{2})\hat{j}+(z-\frac{\pi}{3})\hat{k})(\frac{\sqrt{3} }{2}\hat{i}-\frac{1}{2}\hat{j}+\hat{k})=0\\\frac{\sqrt{3}}{2}x-\frac{5\sqrt{3}}{4}-\frac{1}{2}y+\frac{5\sqrt{3}}{4}+z-\frac{\pi}{3}=0\\\frac{\sqrt{3}}{2}x-\frac{1}{2}y+z=\frac{\pi}{3}$

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3 years ago

I NEED HELP ! Ava's gym membership costs $50 each month plus a one-time $100 fee. Mark's gym membership costs $60 each month plu

asambeis [7]

For Ava if It’s 11 months and for mark it is 15 months and the number is 1,650! (I spent time doing this, and I did. Calculation to make sure you would get this right!)

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3 years ago