$p = 56\% = 0.56 \\ n = 5 \\ q = 1 - p = 0.44 \\ P(X = x) = {n \choose x} {p}^{x} {q}^{(n - x) } \\ P(X < 2) = P(X = 0) + P(X = 1) \\ {5 \choose 0} {0.56}^{0} {0.44}^{(5 - 0) } + {5 \choose 1} {0.56}^{1} {0.44}^{(5 - 1) }$

8 0

3 years ago

x+(x+3)+x^2=75 Please help........ Everyone is giving me answers i know arent true...

son4ous [18]

x + (x + 3) + $x^{2}$ = 75

so you will add up all of the x 's but NOT the x^2

2x + 3 + $x^{2}$ = 75

Rearrange to put the x^2 in front of 2x

$x^{2}$ + 2x + 3 = 75

subtract the 75 from both sides

$x^{2}$ + 2x - 72 = 0

8 0

4 years ago

4/5 ÷ 7/30 please hellllpppp

Softa [21]

Answer:

$\frac{24}{7}$ or $3\frac{3}{7}$

Step-by-step explanation:

$\frac{4}{5}\div \frac{7}{30}$

Step 1: Apply the fraction rule: $\frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}$

$=\frac{4}{5}\times \frac{30}{7}$

Step 2: Cross-cancel common factor: 5

$=\frac{4}{1}\times \frac{6}{7}$

Step 3: Multiply fractions: $\frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}$

$=\frac{4\times \:6}{1\times \:7}$

Step 4: Multiply the numbers: $4\times \:6=24$

$=\frac{24}{1\times \:7}$

Step 5: Multiply the numbers: $1\times \:7=7$

$=\frac{24}{7}$

Therefore, the answer is $\frac{24}{7}$ or in the simplified form; $3\frac{3}{7}$

8 0

3 years ago

?!!!!!!!!!!!!!!!!!!!!!!!

Phoenix [80]

The correct answer is B.

Can I please have brainliest?

8 0

3 years ago

How can you set up this problem?​

How can you set up this problem?