Answer:
The probability that the support granted for 44 projects will not exceed the annual budget is P=0.691.
Step-by-step explanation:
The question is incomplete:
<em>A biotechnology company partially finances ongoing research projects at several North American universities. The annual support granted for each project is determined by the progress of the project and has a </em><em>mean of $22,115 and a standard deviation of $8,145</em><em>. The company has an </em><em>annual budget of $1,000,000</em><em> for supporting research activities. What is the probability that the support granted for </em><em>44 projects</em><em> will n</em><em>ot exceed the annual budget</em><em>? Carry your intermediate computations to at least four decimal places. Report your result to at least three decimal places.</em>
We have to calculate the parameters of the distribution of the sum of money for 44 projects.
We apply the rules for the sum of random variables for the mean and standard deviation.

We can calculate the probabilities of being under the budget as:

It is assumed that the sum of projects money will follow a normal distribution.
Answer:
Step-by-step explanation: u hv 2 make a table for x and y and put in #'s like 1,2,3,4 so u get 1 side of the parabola. x-1, y-11/x-2,y-11/x-3,y-11/x-4,y-14; here u c that u have 2 y's=11 so the points between are the Vertex Points of (2,10)
X has a coefficient, the vertext is (2,10)
Answer:
The median is 2.
Step-by-step explanation:
I just did the test :)
9. 2/6 and in simplified form it’s 1/3
10. 10/4 simplified is 5/2
11. 8/2 simplified is 4/1
12. 7/7 which is 1
13. Has no slope
14. 4/7
The probability of pulling a boys name first is 8/13. Then the probably of pulling a girls second is 2/5.