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2 years ago

Need help with this………

Mathematics

1 answer:

just olya [345]2 years ago

7 0

Answer:

(-4,2)

Step-by-step explanation:

It's the coordinates that the two lines cross at.

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Crawling Crayfish!

boyakko [2]

Answer: Crayfish, 25 s

Step-by-step explanation:

Given

The length of race is 60 cm

Flicker gets a 10 cm head-start

Cray fish covers 6 cm in 5 s i.e. its speed is

$\Rightarrow \dfrac{6}{5}=1.2\ cm/s$

Flicker covers 4 cm in 5 s, its speed is

$\Rightarrow \dfrac{4}{5}=0.8\ cm/s$

Time taken by Cray fish to cover the race is

$\Rightarrow t_1=\dfrac{60}{1.2}\\\\\Rightarrow t_1=50\ s$

Time taken by flicker to cover race with 10 cm head start

$\Rightarrow t_2=\dfrac{60-10}{0.8}\\\\\Rightarrow t_2=62.5\ s$

Time taken by crayfish is less. Hence, crayfish wins the race

When they both covers the same distance, they tied momentarily i.e.

$\Rightarrow 1.2t=10+0.8t\\\Rightarrow 0.4t=10\\\\\Rightarrow t=\dfrac{10}{0.4}\\\\\Rightarrow t=25\ s$

After 25 s, they tied the race.

5 0

3 years ago

Joey and Armando live on the same st as the park. The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando'

AleksandrR [38]

Let's start by assuming Armando's house is between Joey's and the park.

Let $x$ be the distance Joey walked to Armando's house.

The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando's home. Then Joey and Armando walk 3/5 mile to the park.

 $\dfrac{9}{10} = x + \dfrac{3}{5}$

$x = \dfrac{9}{10} - \dfrac{3}{5} = \dfrac{9}{10} -\dfrac{6}{10} = \dfrac{3}{10}$

That's probably the answer they're looking for. But what if the park is between Joey and Armando's houses or Joey is between the park and Armando? (The latter isn't really possible with the given distances.)

Let $a, b, c$ be the distances between three collinear points like we have here. Our equation is really a few equations in one, something like

$\pm a \pm b = \pm c$

Let's get rid of the plus/minuses. Squaring,

$a^2 + b^2\pm 2ab = c^2$

$\pm 2ab = c^2-a^2-b^2$

$4a^2b^2 = (c^2-a^2-b^2)^2$

For us, that's a quadratic equation for $c^2$

$4(9/10)^2(3/5)^2= (c^2-(9/10)^2 - (3/5)^2)^2$

I'll skip right to the solutions,

$c^2=\dfrac{9}{100} \textrm{ or } c^2=\dfrac{9}{4}$

$c=\dfrac{3}{10} \textrm{ or } c=\dfrac{3}{2}$

We could have gotten the 3/2 just by adding 9/10+3/5 but this was more fun.

6 0

3 years ago

18=x/3+6 A) 4 B)12 C)36 D)3

Vesna [10]

Answer:

Step-by-step explanation:

Flip your eq. x/3 + 6 = 18.

Solve (Number on one, variable on other)

+6 -6 = 0. 18-6=12.

Multiply.

12 * 3 = 36.

7 0