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Anestetic [448]

3 years ago

13

A curve that has a radius of 100 m is banked at an angle of θ = 10.4 ∘ . If a 1200 kg car navigates the curve at 65 km / h witho

ut skidding, what is the minimum coefficient of static friction μ s between the pavement and the tires?

1 answer:

Vika [28.1K]3 years ago

3 0

Explanation:

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A 61 kg zebra is traveling 8 m/s east. What is the zebra’s momentum?

klemol [59]

Momentum = Mass × Velocity
   = 61 × 8
   = 488 kg m/s east
   = 500 kg m/s east

Momentum is a vector quantity which means it has a direction as well as a numerical value (fancy word for this is magnitude). This means the final answer should also be in the direction "east".
Furthermore due to the significant figures in the question, the final answer should also be given to 1 sig fig (500) but if you don't want to then I imagine 488 is acceptable. (It's like this because we don't know how accurate we can be with the final answer from the numbers in the question.)

4 0

3 years ago

A three-wheeled car moving along a straight section of road starts from rest, accelerating at 2.00 m/s2 until it reaches a speed

DiKsa [7]

Answer:

(a) Total time = 105.5 sec

(b)average speed = 31.26 m/sec

Explanation:

We have given that three-wheeled car starts from rest that initial velocity u = 0 m/sec

Final velocity = 35 m/sec

Acceleration $a=2m/sec^2$

According to first law of motion we know that v = u+at

So $35=0+2\times t$

t = 17.5 sec

After this car travels 83 sec at a constant speed and after that it takes 5 sec additional time to stop

(a) So total time in which car is in motion = 17.5+83+5 = 105.5 sec

(b) Total distance traveled during first 17.5 sec

$s=ut+\frac{1}{2}at^2=0\times 17.5+\frac{1}{2}\times 2\times 17.5^2=306.25m$

Distance traveled in 83 sec with with velocity of 35 m/sec = $35\times 83=2905m$

For next 5 second

Initial velocity u = 35 m/sec

Final velocity = 0 as finally car stops

So $a=\frac{v-u}{t}=\frac{0-35}{5}=-7m/sec^2$

Distance traveled $s=ut+\frac{1}{2}at^2=35\times 5+\frac{1}{2}\times -7\times 5^2=87.5m$

So total distance traveled = 306.25+2905+87.5 = 3298.75 m

Total time = 105.5 sec

So average speed $=\frac{total\ distance}{total\ time }=\frac{3298.75}{105.5}=31.26m/sec$

5 0

3 years ago

The dispersed particles of a colloid exhibit brownian motion, in which they move _____.

Archy [21]

The dispersed particles of a colloid exhibit brownian motion, in which they move _____. ... The dispersed particles of a colloid exhibit brownian motion, in which they move in a chaotic manner without a discernible pattern.

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3 years ago

Read 2 more answers

Hii please help i’ll give brainliest if you give a correct answer please please hurry it’s timed

Zina [86]

Answer: The answer is A for sure

Explanation:

That is, there will be no acceleration. If you are sitting at rest in a chair and the upward push of the chair is equal to the downward pull of gravity, you will stay at rest in the chair. ... You now have an unbalanced force acting on you and therefore, according to Newton's First Law, your motion is going to change.

Plz give brainlest :)

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Temporary Wind Turbines-

Ronch [10]

Answer:

lol what

Explanation:

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