If you're only dealing with integers, then the answer is:
[-8 , -3)
If you're dealing with real numbers, then the answer is:
[-8, -3)∪(-3, -2)
<span>a) Differentiate both sides of lnq − 3lnp + 0.003p=7 with respect to p, keeping in mind that q is a function of p and so using the Chain Rule to differentiate any functions of q:
(1/q)(dq/dp) − 3/p + 0.003 = 0
dq/dp = (3/p − 0.003)q.
So E(p) = dq/dp (p/q) = (3/p − 0.003)(q)(p/q) = (3/p − 0.003)p = 3 − 0.003p.
b) The revenue is pq.
Note that (d/dp) of pq = q + p dq/dp = q[1 + dq/dp (p/q)] = q(1 + E(p)), which is zero when E(p) = −1. Therefore, to maximize revenue, set E(p) = −1:
3 − 0.003p = −1
0.003p = 4
p = 4/0.003 = 4000/3 = 1333.33</span>
Answer:
f(-2) = 21
Step-by-step explanation:
Step 1: Define
f(x) = 3x² - 4x + 1
f(-2) is x = -2
Step 2: Substitute and Evaluate
f(-2) = 3(-2)² - 4(-2) + 1
f(-2) = 3(4) + 8 + 1
f(-2) = 12 + 9
f(-2) = 21
