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3 years ago

Solve for x ill give brainlest!!!

Mathematics

1 answer:

butalik [34]3 years ago

8 0

Answer:

$x=-9$

Step-by-step explanation:

$36^{x-3}=1296^{x+3}\\(6^2)^{x-3}=(6^4)^{x+3}\\2(x-3)=4(x+3)\\x-3=2x+6\\x+6=-3\\x=-9$

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Answer:

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2 years ago

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Original price is $95 and percent of discount is 35% what is the sale price

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3 years ago

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A positive real number is 6 less than another. If the sum of the square of the two numbers is 38, then finds the numbers.

Serggg [28]

Answer:

There seems to be a typo error but still this has solution.

Let the number be = x

A positive real number is 6 less than another. Means the second will be $(x+6)$

The sum of the square of the two numbers is 38.

$x^{2} +(x+6)^{2} =38$

=> $x^{2} +36+12x+x^{2} =38$

=> $2x^{2}+12x+36 =38$

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=> $2x^{2}+12x-2=0$

Taking out 2 common;

=> $x^{2}+6x-1=0$

Solving this quadratic equation, we get;

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3 years ago

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