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2 years ago

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give me a multistep problem that has at least two amounts of elapsed time a problem that require finding a starting time or endi

ng time

1 answer:

Ilia_Sergeevich [38]2 years ago

4 0

A person leaves the basketball game at 8:30 PM. They are there for six hours and 30 minutes. What time did they arive?

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Which expression represents the greatest common factor (GCF) of 70 and 112? A. 2 x 2 x 2 x 7 B. 2 x 2 x 2 x 5 C. 2 x 7 D. 2 x 2

Mekhanik [1.2K]

Answer:

$\huge\boxed{C. \ \ GCF = 2 * 7}$

Step-by-step explanation:

<u>Firstly, we'll do prime factorization of these numbers.</u>

70 = 2 × 5 × 7

112 = 2 × 2 × 2 × 2 × 7

<u>So, The Greatest Common Factor can be written as:</u>

GCF = 2 × 7 <u>[Since Only one 2 and one 7 is common]</u>

<u></u>

Hope this helped!

<h2>~AnonymousHelper1807</h2>

3 0

3 years ago

Helphelphelphelphelphelppppppp

n200080 [17]

Answer:

Step-by-step explaSimplify the equation by finding the square root of both sides. √x2=x √0=0. x=0. Check: 02=0.

5 0

2 years ago

Identify the correct corresponding parts

andrey2020 [161]

Answer:

The correct corresponding part is;

$\overline {CB}$ ≅ $\overline {CD}$

Step-by-step explanation:

The information given symbolically in the diagram are;

ΔCAB is congruent to ΔCED (ΔCAB ≅ ΔCED)

Segment $\overline {CA}$ is congruent to $\overline {CE}$ ( $\overline {CA}$ ≅ $\overline {CE}$ )

Segment $\overline {CB}$ is congruent to $\overline {CD}$ ( $\overline {CB}$ ≅ $\overline {CD}$ )

From which, we have;

∠A ≅ ∠E by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∠B ≅ ∠D by CPCTC

Segment $\overline {AB}$ is congruent to $\overline {DE}$ ( $\overline {AB}$ ≅ $\overline {DE}$ ) by CPCTC

Segment $\overline {AE}$ bisects $\overline {BD}$

Segment $\overline {BD}$ bisects $\overline {AE}$

Therefore, the correct option is $\overline {CB}$ ≅ $\overline {CD}$

3 0

2 years ago

Find the value of two numbers if their sum is 32 and their difference is 14.

OverLord2011 [107]

23 and 9 are the two numbers

Explanation:

x = one number
y = other number

x + y = 32 {sum of two numbers is 32
x - y = 14 {difference is 14}
-----------
2x = 46 {added the two equations together}
x = 23 {divided both sides by 2}

x + y = 32 {top equation}
23 + y = 32 {substituted 23, in for x, into top equation}
y = 9 {subtracted 23 from both sides}

23 and 9 are the two numbers

4 0

3 years ago

If A = {2, 3, 4, 5} and B = {5, 6, 7, 8}, what is A U B?<br>{2, 3, 4, 5, 6, 7, 8)<br>{5}

Ulleksa [173]

<em>Hey</em><em>!</em><em>!</em><em>!</em><em>!</em>

<em>Here</em><em>'s</em><em> </em><em>you</em><em>r</em><em> </em><em>answer</em><em>:</em>

<em>Sol</em><em>ution</em><em>:</em>

<em>A</em><em>=</em><em>{</em><em>2</em><em>,</em><em>3</em><em>,</em><em>4</em><em>,</em><em>5</em><em>}</em>

<em>B</em><em>=</em><em>{</em><em>5</em><em>,</em><em>6</em><em>,</em><em>7</em><em>,</em><em>8</em><em>}</em>

<em> </em><em>A</em><em> </em><em>U</em><em> </em><em>B</em><em>=</em><em>{</em><em>2</em><em>,</em><em>3</em><em>,</em><em>4</em><em>,</em><em>5</em><em>}</em><em> </em><em>U</em><em> </em><em>{</em><em>5</em><em>,</em><em>6</em><em>,</em><em>7</em><em>,</em><em>8</em><em>}</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>{</em><em>2</em><em>,</em><em>3</em><em>,</em><em>4</em><em>,</em><em>5</em><em>,</em><em>6</em><em>,</em><em>7</em><em>,</em><em>8</em><em>}</em>

<em>In</em><em> </em><em>case</em><em> </em><em>of</em><em> </em><em>Union</em><em>,</em><em>we</em><em> </em><em>have</em><em> </em><em>to</em><em> </em><em>list</em><em> </em><em>all</em><em> </em><em>the</em><em> </em><em>elements</em><em> </em><em>which</em><em> </em><em>are</em><em> </em><em>present</em><em> </em><em>in</em><em> </em><em>both</em><em> </em><em>sets</em><em>.</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>

4 0

3 years ago